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Archy [21]
3 years ago
10

April is an avid chess player. She sets up a coordinate system on her chess board so she can record the position of the pieces d

uring a game. In a recent game, April noted that her king was at (4,2) at the same time that her opponent's king was at (7,8). How far apart were the two kings? Round to the nearest tenth of a unit if necessary.
Mathematics
1 answer:
NemiM [27]3 years ago
4 0

Answer:

6.7

Step-by-step explanation:

To solve this problem, we need to calculate the distance between two points in the XY coordinate plane.

The formula to calculate this distance is:

d = sqrt(dx^2 + dy^2)

where dx is the difference between the X coordinate of the points, dy is the difference between the Y coordinate of the points, and d is the distance.

(sqrt is the square root of what is in the parenthesis)

The first point (April's king) has X=4 and Y=2, the second point (the opponent's king) has X=7 and Y=8.

So, we have that dx = 4-7 = -3 and dy = 2-8 = -6

Now, we calculate the distance:

d = sqrt[ (-3)^2 + (-6)^2 ] = sqrt(9+36) = sqrt(45) = 6.7082 = 6.7

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Answer:

= 9.2 cm

Step-by-step explanation:

D = C ÷ π

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3 years ago
What is the rate of change of y with respect to x for this function?<br> HELP FOR BRAINLYEST
Pepsi [2]
First let's assume that the table contains points on a straight line.  Then all we have to do is to determine the slope of that line.

Suppose we go from (0,3) to (7,-28.5).
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Then the slope, m, is m = ------------- = ---------- = - 9/2, or - 4.5.
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Let's check this result!

Suppose that y = mx + b governs the relationship between x and y.


Then y = -4.5x + b

suppose we find b by substituting the coordinates from the point (0,3):

3 = -4.5(0) + b

Then b = 3, and y = -4.5x + 3.  Does the point (-2,12) satisfy this equation?

Does 12 = -4.5(-2) + 3?  Does 12 = 9 + 3?  YES.

So y = -4.5x + 3 is the equation from which these points came, and the rate of change of y with respect to x is the slope m = -4.5, or m = -9/2.

6 0
4 years ago
Find the point P on the graph of the function y=√x closest to the point (9,0)
Sphinxa [80]

Answer:

\displaystyle \frac{17}{2}.

Step-by-step explanation:

Let the x-coordinate of P be t. For P\! to be on the graph of the function y = \sqrt{x}, the y-coordinate of \! P would need to be \sqrt{t}. Therefore, the coordinate of P \! would be \left(t,\, \sqrt{t}\right).

The Euclidean Distance between \left(t,\, \sqrt{t}\right) and (9,\, 0) is:

\begin{aligned} & d\left(\left(t,\, \sqrt{t}\right),\, (9,\, 0)\right) \\ &= \sqrt{(t - 9)^2 +\left(\sqrt{t}\right)^{2}} \\ &= \sqrt{t^2 - 18\, t + 81 + t} \\ &= \sqrt{t^2 - 17 \, t + 81}\end{aligned}.

The goal is to find the a t that minimizes this distance. However, \sqrt{t^2 - 17 \, t + 81} is non-negative for all real t\!. Hence, the \! t that minimizes the square of this expression, \left(t^2 - 17 \, t + 81\right), would also minimize \sqrt{t^2 - 17 \, t + 81}\!.

Differentiate \left(t^2 - 17 \, t + 81\right) with respect to t:

\displaystyle \frac{d}{dt}\left[t^2 - 17 \, t + 81\right] = 2\, t - 17.

\displaystyle \frac{d^{2}}{dt^{2}}\left[t^2 - 17 \, t + 81\right] = 2.

Set the first derivative, (2\, t - 17), to 0 and solve for t:

2\, t - 17 = 0.

\displaystyle t = \frac{17}{2}.

Notice that the second derivative is greater than 0 for this t. Hence, \displaystyle t = \frac{17}{2} would indeed minimize \left(t^2 - 17 \, t + 81\right). This t\! value would also minimize \sqrt{t^2 - 17 \, t + 81}\!, the distance between P \left(t,\, \sqrt{t}\right) and (9,\, 0).

Therefore, the point P would be closest to (9,\, 0) when the x-coordinate of P\! is \displaystyle \frac{17}{2}.

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