Question

Section 5.2-9. Solve the following system of equations by substitution or elimination. Enter your answer as (x,y).2x+y = 2-3x-2y = -8

Answer 1

Answer: In terms of (x,y), using substitution, the answer is (-4,10)

Step-by-step explanation:

y=2-2x

-3x-2y=-8

~

-3x-2(2-2x)=-8

-3x-4+4x=-8

x-4=-8

x=-4

~

y=2-2(-4)

y=2+8

y=10

Answer 2

$\begin{gathered} (2x+y=2)\times2 \\ -3x-2y=-8 \\ 4x+2y=4 \\ -3x-2y=-8 \\ \text{subtract above two equations} \\ x=-4 \\ \text{put the value of x in equation 1st then get y} \\ 4(-4)+2y=4 \\ -16+2y=4 \\ 2y=20 \\ y=10 \\ (x,y)=(-4,10) \end{gathered}$