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stiv31 [10]
3 years ago
15

Help please will give you points

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
4 0

Answer:

16

Step-by-step explanation:

From the question given above, the following data were obtained:

Sum of N term (Sₙ) = 292

2nd term (T₂) = 8.5

5th term (T₅) = 13

Number of terms (N) =?

Next, we shall determine the first term (a) and the common difference (d) of the series. This can be obtained as follow:

T₂ = a + d

8.5 = a + d ........ 1

T₅ = a + 4d

13 = a + 4d ........ 2

Subtract equation 1 from equation 2 i.e

(2) – (1)

.. 13 = a + 4d

– 8.5 = a + d

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

4.5 = 3d

Divide both side by 3

d = 4.5 / 3

d = 1.5

Substitute the value of d into any of the equation to obtain the value of a. Here, we shall use equation 1.

8.5 = a + d

d = 1.5

8.5 = a + 1.5

Collect like terms

8.5 – 1.5 = a

a = 7

Finally, we shall determine the number of terms as follow:

Sum of N term (Sₙ) = 292

Common difference (d) = 1.5

First term (a) = 7

Number of terms (N) =?

Sₙ = n/2[2a + (n – 1)d]

292 × 2 = n[(2 × 7) + (n – 1)1.5]

584 = n[14 + 1.5n – 1.5]

584 = n[12.5 + 1.5n]

584 = 12.5n + 1.5n²

Rearrange

1.5n² + 12.5n – 584 = 0

Using formula method, the value of n can be obtained as follow:

a = 1.5

b = 12.5

c = –584

n = –b ± √(b² – 4ac) / 2a

n = –12.5 ± √(12.5² – 4 × 1.5 × –584) / 2 × 1.5

n = –12.5 ± √(156.25 + 3504) / 3

n = –12.5 ± √(3660.25) / 3

n = –12.5 ± 60.5 / 3

n = –12.5 + 60.5 / 3 or –12.5 – 60.5 / 3

n = 4 /3 or –73 / 3

n = 16 or –73 / 3

Since the number of terms can not be negative, therefore, the number of term is 16

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<h2>Answer:</h2>

The ratio of the area of region R to the area of region S is:

                    \dfrac{24}{25}

<h2>Step-by-step explanation:</h2>

The sides of R are in the ratio : 2:3

Let the length of R be: 2x

and the width of R be: 3x

i.e. The perimeter of R is given by:

Perimeter\ of\ R=2(2x+3x)

( Since, the perimeter of a rectangle with length L and breadth or width B is given by:

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Hence, we get:

Perimeter\ of\ R=2(5x)

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Perimeter\ of\ R=10x

Also, let " s " denote the side of the square region.

We know that the perimeter of a square with side " s " is given by:

\text{Perimeter\ of\ square}=4s

Now, it is given that:

The perimeters of square region S and rectangular region R are equal.

i.e.

4s=10x\\\\i.e.\\\\s=\dfrac{10x}{4}\\\\s=\dfrac{5x}{2}

Now, we know that the area of a square is given by:

\text{Area\ of\ square}=s^2

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\text{Area\ of\ Rectangle}=6x^2

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