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3 years ago

Please help I have tried multiple times but keep getting it wrong.

Mathematics

1 answer:

VladimirAG [237]3 years ago

3 0

Answer:

inequality form: x

x≤ 4 or x≥8

Interval Notation:

(-∞, 4] U[8,∞)

Explanation

Solve the following inequality, then graph the solution set. | x | − 6 ≥ − 4. Answer in interval notation.

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One more piece of information is given than is necessary for solving the problem. Identify this unnecessary piece of information

icang [17]

Answer:

D. is not necessary

Step-by-step explanation:

12 in=60 feet

15 in =75 feet

4 0

3 years ago

Can someone help me with this

Gennadij [26K]

Answer:

k = 4

Step-by-step explanation:

The two points shown are ...

g(1) = 10

f(4) = 10

Comparing this to the given relation, we can see that ...

g(x) = f(kx)

g(1) = f(4)

x=1 and kx =4, so k=4.

8 0

3 years ago

Three times the sum of half carlita's age and 3 is at least 12 .what values represent carlita's possible age? Graph the solution

Naya [18.7K]

Answer:

18 years

Step-by-step explanation:

let catrinas age be c

3(c/2)+3=12

3c/6=9

3c=54

c=18

6 0

3 years ago

Is anyone able to figure this out, I can't do this

katrin [286]

Answer:

C. √2 - 1

Step-by-step explanation:

If we draw a square from the center of the large circle to the center of one of the small circles, we can see that the sides of the square are equal to the radius of the small circle (see attached diagram)

Let r = the radius of the small circle

Using Pythagoras' Theorem $a^2+b^2=c^2$

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

to find the diagonal of the square:

$\implies r^2 + r^2 = c^2$

$\implies 2r^2 = c^2$

$\implies c=\sqrt{2r^2}$

So the diagonal of the square = $\sqrt{2r^2}$

We are told that the radius of the large circle is 1:

⇒ Diagonal of square + r = 1

$\implies \sqrt{2r^2}+r=1$

$\implies \sqrt{2r^2}=1-r$

$\implies 2r^2=(1-r)^2$

$\implies 2r^2=1-2r+r^2$

$\implies r^2+2r-1=0$

Using the quadratic formula to calculate r:

$\implies r=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\implies r=\dfrac{-2\pm\sqrt{2^2-4(1)(-1)}}{2(1)}$

$\implies r=\dfrac{-2\pm\sqrt{8}}{2}$

$\implies r=-1\pm\sqrt{2}$

As distance is positive, $r=-1+\sqrt{2}=\sqrt{2}-1$ only

5 0

2 years ago

Read 2 more answers

PLEASE HELP ME!!! NO LINKS OR SITES, JUST THE ANSWER, THANK YOU!!

Helen [10]

Answer:

3.75

Step-by-step explanation:

12t = 45

t = 3.75

I hope this is correct

8 0

3 years ago

Read 2 more answers