To compare the two classes, the Coefficient of Variation (COV) can be used. The formula for COV is this:
C = s / x
where s is the standard deviation and x is the mean
For the first class:
C1 = 10.2 / 75.5
C1 = 0.1351 (13.51%)
For the second class:
C2 = 22.5 / 75.5
C2 = 0.2980 (29.80%)
The COV is a test of homogeneity. Looking at the values, the first class has more students having a grade closer to the average than the second class.
Answer:
= r²−4r+3
Step-by-step explanation:
(r - 3) (r - 1)
(r x r) + (r x -1) + (-3 x r) + (-3 x -1)
r² + - r - 3r + 3
= r²−4r+3
Answer:
3,406.5 litres/hr
Step-by-step explanation:
The liquid is being poured at a rate of 15 gallons per minute.
1 minute = 1/60 hour
Thus, the rate can be written as:
15 gallons pet 1/60 hour
We are told that one gallon is approximately 3.785 liters.
Thus;
15 gallons = 15 × 3.785 litres = 56.775 litres.
Thus, the rate is;
56.775 litres per 1/60 hour
We want to find in litres/hr.
By proportion, we have it as;
(56.775 ÷ 1/60)/1 = 56.775 × 60 = 3,406.5 litres/hr
Answer:
power=work done/time
work done= 99N
Step-by-step explanation:
