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Zinaida [17]
3 years ago
5

A race car travels 100 feet in .5 seconds. At this rate of speed, how many feeet will the race car travel in a minute?

Mathematics
2 answers:
snow_tiger [21]3 years ago
7 0

\text{Hello there!}\\\\\text{We know that a car travels 100 ft every .5 seconds}\\\\\text{Lets find how far it goes every second}\\\\100*2=200\,\text{ft per second}\\\\\text{We're trying to find how far it goes in a minute, so multiply by 60}\\\text{Since 60 seconds = 1 minute}\\200*60=12000\\\\\boxed{12,000 ft}

soldier1979 [14.2K]3 years ago
5 0

Answer:

Step-by-step explanation:

\frac{100ft}{0.5s} * 60s

\frac{100 * 60}{0.5}

\frac{6000}{0.5}

12000ft

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6(m-1) = 3(3m + 2) Show all work
nordsb [41]

Answer:

\boxed{\sf m = -4}

Step-by-step explanation:

\sf Solve \:  for  \: m: \\  \sf \implies 6 (m - 1) = 3 (3 m + 2) \\  \\  \sf Expand \:  out  \: terms \:  of \:  the \:  left  \: hand \:  side: \\  \sf \implies 6 m - 6 = 3 (3 m + 2) \\  \\  \sf Expand \:  out  \: terms  \: of  \: the  \: right \:  hand \:  side: \\  \sf \implies 6 m - 6 = 9 m + 6 \\  \\  \sf Subtract \:  9 m  \: from  \: both  \: sides: \\  \sf \implies (6 m - 9 m) - 6 = (9 m - 9 m) + 6 \\  \\  \sf 6 m - 9 m = -3 m: \\  \sf \implies -3 m - 6 = (9 m - 9 m) + 6 \\  \\  \sf 9 m - 9 m = 0: \\  \sf \implies -3 m - 6 = 6 \\  \\  \sf Add  \: 6 \:  to \:  both  \: sides: \\  \sf \implies (6 - 6) - 3 m = 6 + 6 \\  \\  \sf 6 - 6 = 0: \\  \sf \implies -3 m = 6 + 6 \\  \\  \sf 6 + 6 = 12: \\  \sf \implies -3 m = 12 \\  \\  \sf Divide  \: both  \: sides  \: of \:  -3 m = 12 \:  by \:  -3: \\  \sf \implies  \frac{ - 3m}{ - 3}  =  \frac{12}{ - 3}  \\  \\  \sf \frac{ - 3}{ - 3} = 1: \\  \sf \implies m =  \frac{12}{ - 3}  \\  \\  \sf -  \frac{12}{3}  =  - 4 :  \\  \sf \implies m =  - 4

7 0
3 years ago
Solve for y2. d = y2- y1
kvasek [131]
D=y2-y1
D+y1= y2-y1+y1 add y1 to both sides to cancel it out.

D+y1=y2 that drops -y1 for the right side but the left remains.

And that's your answer.
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Answer:

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