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Nookie1986 [14]

3 years ago

7

Factor the quadratic x2+ 3x − 10. Explain your process for factoring and rewrite the original quadratic in factored form

2 answers:

Lorico [155]3 years ago

4 0

The first thing you must do is to find factors that equal to -10
1 x -10, -10 x 1, -2 x 5 and -5x 2. Then of these four groups of factor we chose the one that when the two factors are added equals to 3. So -2 x 5 equals 3
So are answer is
(x-2)(x+5)

Neporo4naja [7]3 years ago

3 0

Answer:

(x-2)(x+5)

Step-by-step explanation:

when factoring, our equation should be in this format: (x+__) (x+__) Then we have to find numbers that add up to 3 but multiply to -10 aka -2 and 5. -2+5=3 and -2(5)= -10

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Travka [436]

Answer:

$y=0.25x+4.25$

Step-by-step explanation:

<u>Step 1: Determine the two forms</u>

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Slope Intercept Form → $y=mx+b$

<u>Step 2: Plug into point slope form</u>

$(y-4)=0.25(x-(-1))$

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<u>Step 3: Convert to slope intercept form</u>

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3 years ago

Solve for x in the equation x^2+2x+1=17

dybincka [34]

Answer:

x= (-1+ √17) or (-1-√17)

Step-by-step explanation:

In this question, we have to solve for x from the given equation x² +2x+1 =17

Now, the equation can be rearranged to x² +2x -16 =0.

Here we can not apply the process of factorization to get the value of x.

Hence, we will use the Shridhar Acharya formula to solve the value of x.

{This formula gives, if ax² +bx +c =0 then, the value of x can be solved as

x=[-b±√(b²-4ac)]/2a }

Hence, in this case, the solution for x will be

x= $\frac{-2+\sqrt{2^{2}-4(1)(-16) } }{2(1)} or \frac{-2-\sqrt{2^{2}-4(1)(-16) } }{2(1)}$

⇒ x= $\frac{-2+2\sqrt{17} }{2} or \frac{-2-2\sqrt{17} }{2}$

⇒ x= (-1+ √17) or (-1-√17) (Answer)

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4 years ago

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Step-by-step explanation:

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3 years ago

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kykrilka [37]

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