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alex41 [277]
3 years ago
6

1) A population of bees is increasing at a rate of 8% per week. If

Mathematics
1 answer:
ad-work [718]3 years ago
3 0

Answer:

≈387,7

Step-by-step explanation:

I hope it's right. Sorry if it's not right.

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Nick has to build a brick wall. Each row of the wall requires 62 bricks. There are 10 rows in the wall. How many bricks will Nic
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Nick will need 620 bricks.
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Find the number that makes the ratio equivalent to 1:2.<br> 9:
Y_Kistochka [10]

Answer:

9:18

Step-by-step explanation:

1:2 means that you have to multiply the first number by 2 to get the second number. Therefore, you have to multiply 9 by 2, which is equal to 18. Therefore, it would be 9:18.

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3 years ago
What is y-1 =2(x +3) in standard form?
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Answer:

y-1=2(x+3)

y-1=2x+6

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4 years ago
A sequence of Bernoulli trials consists of choosing components at random from a batch of components. A selected component is eit
Drupady [299]

Answer:

a) 0.0287 = 2.87% probability that three non-defective components in a batch of seven components.

b) 0.0336 = 3.36% probability that 8 non-defective components are drawn before the first defective component is chosen.

Step-by-step explanation:

A sequence of Bernoulli trials composes the binomial distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a selected component is non-defective is 0.8

This means that p = 0.8

a) Three non-defective components in a batch of seven components.

This is P(X = 3) when n = 7. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{7,3}.(0.8)^{3}.(0.2)^{4} = 0.0287

0.0287 = 2.87% probability that three non-defective components in a batch of seven components.

b) 8 non-defective components are drawn before the first defective component is chosen.

Now the order is important, so the we just multiply the probabilities.

8 non-defective, each with probability 0.8, and then a defective, with probability 0.2. So

p = (0.8)^8*0.2 = 0.0336

0.0336 = 3.36% probability that 8 non-defective components are drawn before the first defective component is chosen.

4 0
3 years ago
PLSS HELPP MMEEE FASSTT
marta [7]

Answer:

12313

Step-by-step explanation:

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