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3 years ago

1. A number that is a factor of two or more numbers is a ________________.

1 answer:

6 0

Hi! Here are my answers for this:

1. common factor
2. common multiple
3. divisible
4. pattern
5. term

I hope that helps!

You might be interested in

F(x)= <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4x%20-%207%7D%7B10%7D%20" id="TexFormula1" title=" \frac{4x - 7}{10} "

Naily [24]

Answer:

To find f-¹(x) of f(x) equate f(x) to y

That's

f(x) = y

So we have

$y = \frac{4x - 7}{10}$

Next interchange the variables that's x becomes y and y becomes x

That's

$x = \frac{4y - 7}{10}$

Next make y the subject

Cross multiply

We have

4y - 7 = 10x

Move -7 to the right side of the equation

4y = 10x + 7

Divide both sides by 4

We have the final answer as

$y = \frac{10x + 7}{4}$

$f ^{ - 1} (x) = \frac{10x + 7}{4}$

Hope this helps you

7 0

3 years ago

A number, x, rounded to 1 decimal place is 3.7<br>Write down the error interval for x.

alekssr [168]

Answer:

$3.65 \leqslant x \leqslant 3.75$

Step-by-step explanation:

The error in rounding a number is half of the unit of measure.

The number was rounded to the nearest 0.1 unit so the error is 1/2×0.1, which equals 0.05.

Now we add 3.7 and 0.05, which equals 3.75 and we also take 3.7 - 0.05, which equals 3.65

So, the error interval is:

$3.65 \leqslant x \leqslant 3.75$

4 0

3 years ago

Let μ denote the true average radioactivity level(picocuries per liter). The value 5 pCi/L is considered thedividing line betwee

VMariaS [17]

Answer:

H0: μ = 5 versus Ha: μ < 5.

Step-by-step explanation:

Given:

μ = true average radioactivity level(picocuries per liter)

5 pCi/L = dividing line between safe and unsafe water

The recommended test here is to test the null hypothesis, H0: μ = 5 against the alternative hypothesis Ha: μ < 5.

A type I error, is an error where the null hypothesis, H0 is rejected when it is true.

We know type I error can be controlled, so safer option which is to test H0: μ = 5 vs Ha: μ < 5 is recommended.

Here, a type I error involves declaring the water is safe when it is not safe. A test which ensures that this error is highly unlikely is desirable because this is a very serious error. We prefer that the most serious error be a type I error because it can be explicitly controlled.

7 0

2 years ago

Any volunteer please help

den301095 [7]

Answer:

Part A)

The equation in the point-slope form is:

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Part B)

The graph of the equation is attached below.

Step-by-step explanation:

Part A)

Given

The point = (-2, 11)

m = 4/3

The point-slope form of the line equation is

$y-y_1=m\left(x-x_1\right)$

Here, m is the slope and (x₁, y₁) is the point

substituting the values m = 4/3 and the point (-2, 11) in the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Thus, the equation in the point-slope form is:

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Part B)

As we have determined the point-slope form which passes through the point (-2, 11) and has a slope m = 4/3

The graph of the equation is attached below.

5 0

3 years ago

What is 5% of 20?<br> Please help me

zloy xaker [14]

Answer:

Step-by-step explanation:

5% × 20 =

(5 ÷ 100) × 20 =

(5 × 20) ÷ 100 =

100 ÷ 100 =

3 0

3 years ago

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