All categories

2 years ago

Use a calculator to find the approximate value of sin-1 (0.549)

2 answers:

6 0

This is the concept of algebra, we are required to approximate the arcsin of the value given using a calculator;
sin theta=[opposite]/[hypotenuse]
arcsin is the inverse of sin, thus;
arcsin(0.549)=33.2984
the answer is 33.3984°

tester [92]2 years ago

6 0

Answer: 33.30°

Step-by-step explanation:First, make sure your calculator is in DEG

Then press shift and then sin, then insert your number 0.549 and then press the equality sign(=)

You will have the answer 33.3 approximately.

You might be interested in

The histogram below shows information about the number of books students read in a month:

max2010maxim [7]

Answer:

Option C is true - The number of students who read 4 books or fewer

Step-by-step explanation:

Here, to find the mean and median, we do not have proper information or specific values. We just have the ranges, so both the mean and median cannot be determined. So, options A and B are not correct.

We can see two bins covering the 9 or more books, so option D cannot be true either.

Therefore, only option C is left and that is true.- the number of students who read 4 books or fewer.

6 0

3 years ago

How do I write the ordered pair that represents yz. Then how do I find the magnitude of yz. Y(14,-23), Z(23,-14)

kaheart [24]

Answer:answer is A on edge

Step-by-step explanation:

3 0

3 years ago

Find f(a), f(a+h), and 71. f(x) = 7x - 3 f(a+h)-f(a) h if h = 0. 72. f(x) = 5x²

Leni [432]

Answer:

$71. \ \ \ f(a) \ = \ 7a \ - \ 3; \ f(a+h) \ = \ 7a \ + \ 7h \ - \ 3; \ \displaystyle\frac{f(a+h) \ - \ f(a)}{h} \ = \ 7$

$72. \ \ \ f(a) \ = \ 5a^{2}; \ f(a+h) \ = \ {5a}^{2} \ + \ 10ah \ + \ {5h}^{2}; \ \displaystyle\frac{f(a+h) \ - \ f(a)}{h} \ = \ 10a \ + \ 5h$

Step-by-step explanation:

In single-variable calculus, the difference quotient is the expression

$\displaystyle\frac{f(x+h) \ - \ f(x)}{h}$ ,

which its name comes from the fact that it is the quotient of the difference of the evaluated values of the function by the difference of its corresponding input values (as shown in the figure below).

This expression looks similar to the method of evaluating the slope of a line. Indeed, the difference quotient provides the slope of a secant line (in blue) that passes through two coordinate points on a curve.

$m \ \ = \ \ \displaystyle\frac{\Delta y}{\Delta x} \ \ = \ \ \displaystyle\frac{rise}{run}$ .

Similarly, the difference quotient is a measure of the average rate of change of the function over an interval. When the limit of the difference quotient is taken as h approaches 0 gives the instantaneous rate of change (rate of change in an instant) or the derivative of the function.

Therefore,

$71. \ \ \ \ \ \displaystyle\frac{f(a \ + \ h) \ - \ f(a)}{h} \ \ = \ \ \displaystyle\frac{(7a \ + \ 7h \ - \ 3) \ - \ (7a \ - \ 3)}{h} \\ \\ \-\hspace{4.25cm} = \ \ \displaystyle\frac{7h}{h} \\ \\ \-\hspace{4.25cm} = \ \ 7$

$72. \ \ \ \ \ \displaystyle\frac{f(a \ + \ h) \ - \ f(a)}{h} \ \ = \ \ \displaystyle\frac{{5(a \ + \ h)}^{2} \ - \ {5(a)}^{2}}{h} \\ \\ \-\hspace{4.25cm} = \ \ \displaystyle\frac{{5a}^{2} \ + \ 10ah \ + \ {5h}^{2} \ - \ {5a}^{2}}{h} \\ \\ \-\hspace{4.25cm} = \ \ \displaystyle\frac{h(10a \ + \ 5h)}{h} \\ \\ \-\hspace{4.25cm} = \ \ 10a \ + \ 5h$

4 0

1 year ago

Can I please have help?

givi [52]

-12+-12=-24
-6+-6=-12
-11+-11=-22
-10+-10=-20
-9+-9=-18
-8+-8=-16
-7+-7=-14
-5+-5=-10
-4+-4=-8
-3+-3=-6
-1+-1=-2
1+1=2
2+2=4
3+3=6
4+4=8
5+5=10
6+6=12

8 0

2 years ago

Which word has almost the same meaning as the word drawbacks? 1st person to answer get brainlyest

iogann1982 [59]

Answer:

Step-by-step explanation:

cross out

3 0

2 years ago

Read 2 more answers