Answer:
One robot will be powered for an eighth of a day (1/8 of a day) by one quarter (1/4) of a bag of coffee.
Answer:
Step-by-step explanation:
It is a rectangle, so both sides are equal. Thus 2x+6=5x-9
SOLVE, SUBTRACT 2x
6=3x-9 THEN ADD 9
15=3x THEN divide by 3
5=x
Plug in x to either side 2(5)+6, to get side length of 16
Then area of a rectangle is lengthxwidth=AREA
substitute what you know 16(y)=48
Divide by 16, thus y=3
There will be 15 orange pickles and 10 green picks
Answer: if you times 12x2.75 I got 33 some she can spend $33.00 and not go over.
A) zeroes
P(n) = -250 n^2 + 2500n - 5250
Extract common factor:
P(n)= -250 (n^2 - 10n + 21)
Factor (find two numbers that sum -10 and its product is 21)
P(n) = -250(n - 3)(n - 7)
Zeroes ==> n - 3 = 0 or n -7 = 0
Then n = 3 and n = 7 are the zeros.
They rerpesent that if the promoter sells tickets at 3 or 7 dollars the profit is zero.
B) Maximum profit
Completion of squares
n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4
P(n) = - 250[(n-5)^2 -4] = -250(n-5)^2 + 1000
Maximum ==> - 250 (n - 5)^2 = 0 ==> n = 5 and P(5) = 1000
Maximum profit =1000 at n = 5
C) Axis of symmetry
Vertex = (h,k) when the equation is in the form A(n-h)^2 + k
Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000
Vertex = (5, 1000) and the symmetry axis is n = 5.
