Lola already has 6 pennies, and she plans to save more. In her first week of saving pennies, she will save twice the
1 answer:
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Esta é a trigonometria . Se você desenhar uma linha a partir do topo da casa de luz para o barco, você terá a hypotonuse de um triângulo. Um truque é lembrar que este é um triângulo especial. É um triângulo 30-60-90 , que tem propriedades especiais mostradas na fixação abaixo . por isso sabemos que o lado adjacente que não é o hyposonuse é x√3 . Agora sabemos que x<span>√3 = 20
Solve for x.
x</span><span>√3=20
divide both sides by </span><span>√3.
x=20/(</span><span><span>√3)
</span>Try not to have square roots (</span><span><span>√)</span> in denomenator so multiply top and bottom by </span><span>√3 and get
x=(20</span><span>√3)/3
x is what we are looking for so the answer is </span>
20<span>√3 m </span><span>ou cerca de 34.64 m</span>
Solve for x.
x</span><span>√3=20
divide both sides by </span><span>√3.
x=20/(</span><span><span>√3)
</span>Try not to have square roots (</span><span><span>√)</span> in denomenator so multiply top and bottom by </span><span>√3 and get
x=(20</span><span>√3)/3
x is what we are looking for so the answer is </span>
20<span>√3 m </span><span>ou cerca de 34.64 m</span>
Answer: Missing parts are,
In first blank, ,
In second blank, SAS postulate
In third blank, CPCTC postulate
Step-by-step explanation:
Since, Here D is the mid point on the line segment AC.
And BD is a perpendicular to the line AC.
Therefore, In triangles ADB and CDB ( shown in figure)
AD\cong DC ( By the definition of mid point)
( right angles )
( reflexive)
Thus, By SAS ( side angle side )postulate,
So, by CPCTC( Corresponding parts of congruent triangles are congruent)
Now, By definition of congruent segment,
AB=CB
By definition of equidistant,
B is equally far from both A and C.
