Answer:
Step-by-step explanation:
We have the equations
4x + 3y = 18 where x = the side of the square and y = the side of the triangle
For the areas:
A = x^2 + √3y/2* y/2
A = x^2 + √3y^2/4
From the first equation x = (18 - 3y)/4
So substituting in the area equation:
A = [ (18 - 3y)/4]^2 + √3y^2/4
A = (18 - 3y)^2 / 16 + √3y^2/4
Now for maximum / minimum area the derivative = 0 so we have
A' = 1/16 * 2(18 - 3y) * -3 + 1/4 * 2√3 y = 0
-3/8 (18 - 3y) + √3 y /2 = 0
-27/4 + 9y/8 + √3y /2 = 0
-54 + 9y + 4√3y = 0
y = 54 / 15.93
= 3.39 metres
So x = (18-3(3.39) / 4 = 1.96.
This is a minimum value for x.
So the total length of wire the square for minimum total area is 4 * 1.96
= 7.84 m
There is no maximum area as the equation for the total area is a quadratic with a positive leading coefficient.
Length of GH is also 11 meters
The graph of f(x) = (x – 8)^3 + 4, is the parent graph [g(x) = x^3] transformed 8 units to the right, and transformed 4 units up
Answer:
1) 8
Step-by-step explanation:
3+2 is 5
4^2 is 16
16×5=80
2×5=10
80÷10=8
Your equation for number one is 600,788,188/760,507,625 = x/100
After cross multiplying you will get 760,507,625x = 60,078,818,800
Then you will divide by <span>760,507,625 to isolate the varible to get 78.99 = x.
Your equation in number two is 80/143 = x/100 because when you subtract 143 by 63 you get 80, the amount of males in the room. Then you cross multiply to get, 143x = 8000. Then you would divide both sides by 143 to isolate the varible to get 55%</span>
