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nalin [4]
2 years ago
5

Please help___________​

Mathematics
1 answer:
kramer2 years ago
4 0

Answer:

Step-by-step explanation:

Let's do the obvious things first.

Right rectangle

w = 11

L = 17

Formula

Area = L * W

Area = 11 * 17

Area =                                                187

Left rectangle

W = 8

L = 11

Area = 8 * 11=                                      88

Middle Rectangle

W = 11

L = 15

Area = 11 * 15                                    165

Now we come to the triangles. It's not obvious what to do with them. You have to infer that one of the lets is 8 and the other is 15. You get the 8 from the width of the left rectangle (see above.)

There are 2 triangles

Area = 2 * 1/2 * l1 * l2

Leg 1 = 8

Leg2 = 15

Area = 2 * 1/2 (8 * 15)

Area =               <u>                            120 </u>

Total  = 120 + 165 + 88 + 187 =    560

Unless you have an  E answer that is 560, my answer does not agree with any of the given answers. I would suggest that you ask your teacher how it is done. My method is correct.

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Triangle TRS is similar to triangle TMN. Angle T = 40°, angle R = 60°, and angle S = 80° . What is the measure of angle M
Andre45 [30]

Answer:

60degrees

Step-by-step explanation:

For similar triangles, the angles of their angles are equal to matter the size.

Hence if triangle TRS is similar to triangle TMN, then;

<R = <M and <S = <N

Given that;

<T = 40 degrees

<R = 60degrees

<S = 80 degrees

Since <R = <M, then <M = 60degrees

7 0
2 years ago
The gym is filled with 215 students &amp; adults. Student tickets are $.50 and adults are $2.00. If $250.00 was collected, how m
BARSIC [14]
In order to determine the correct answer, it would be helpful to set up equations. We do as follows:

Let x = students
      y = adults

x + y = 215
.50x + 2y = 250

SOlving simultaneously, we have:

x = 120 students 
y = 95 adults

Hope this answers the question. Have a nice day.
3 0
3 years ago
Suppose Sally has $28.00 in her bank account and starts saving $18.25 every week. Her friend Suzy has $161.00 in her bank accoun
Elza [17]

a.

Sally has $28.00 in her bank account and starts saving $18.25 every week.

Let x represent the number of weeks from when he have $28.00 in her account.

and y represent the amount in her account at week x;

We can write the function of the case as;

y=mx+b

where m is the amount she saves every week, and b the initial amount in her account.

\begin{gathered} m=\text{ \$18.25} \\ b=\text{ \$28.00} \end{gathered}

So, the function will be;

y=18.25x+28

b.

Her friend Suzy has $161.00 in her bank account and is withdrawing $15 every week.​

Using the same rule as in a above;

\begin{gathered} m=-15\text{ (withdrawing is negative)} \\ b=161 \end{gathered}

The function will be;

y=-15x+161

c.

The graph of the two functions is shown below;

d.

The point where the two lines intersect is shown in the graph above.

The point is at;

(4,101)

Which is at week 4 and balance $101.

e.

The point at which they intersect is the point where they both have the same values.

It is the week when both Sally and Suzy have the same amount in there account.

So, at the fourth week (week 4) Sally and Suzy both have $101 in their account

3 0
1 year ago
-
Contact [7]

Answer:

c

Step-by-step explanation:

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5 0
3 years ago
A researchers wants to determine the mean weight of avocados grown in Southern California. The population from which the sample
natka813 [3]

Answer: (0.465, 5.535)

Step-by-step explanation:

Formula to calculate the confidence interval (<em>when population standard deviation is unknown</em>) is given by :-

\overline{x}\pm t_{\alpha/2} \dfrac{s}{\sqrt{n}}

, where \overline{x} = sample mean.

s= sample standard deviation.

n= Sample size.

t_{\alpha/2} = critical value

By considering the given information , we have

\overline{x}=6

s=0.75

n= 9

Significance level = \alpha=0.1   [1-0.90=0.1]

By using students' t distribution -table , the critical value for 95% confidence level :

t_{\alpha/2 , n-1}=t_{0.1/2,\ 8}=1.86

[Note: degree of freedom = n-1]

Now, the 90% confidence interval for the true mean weight of these Southern California avocados will be :

6\pm (1.86) \dfrac{0.75}{\sqrt{9}}

6\pm (1.86) \dfrac{0.75}{3}

6\pm (1.86) 0.25

6\pm 0.465=(6-0.465,\ 6+0.465)=(0.465,\ 5.535)

Hence, the required confidence interval  =(0.465, 5.535)

4 0
3 years ago
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