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3 years ago

HELLLLLLLPPPPPPPPPPPP

Mathematics

2 answers:

elena55 [62]3 years ago

5 0

Answer:

250

5:15

true

i already helped you

White raven [17]3 years ago

3 0

Answer:

9- 4 hours 30 minutes

10- 250

11- False

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List the first 5 multiples of 4. * Your answer

posledela

Answer:

4,8,12,16,20

Step-by-step explanation:

3 0

3 years ago

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The function y=60+25sin(pi/6)t, where t is in months and t=0 corresponds to April 15, models the average high temperature in deg

BartSMP [9]

Answer:

The maximum temperature will be of 85 degrees, on July 15.

Step-by-step explanation:

Sine function:

The sine function oscilates between -1 and 1, and it's maximum value is:

$\sin{(\frac{\pi}{2})} = 1$

y=60+25sin(pi/6)t

The maximum value will occur when $\sin{(\frac{\pi t}{6}}) = 1$ , and it will be of 60 + 25 = 85 degrees.

When will it occur?

First we find the value of t for which the value inside the function sine is $\frac{\pi}{2}$ . So

$\frac{\pi t}{6} = \frac{\pi}{2}$

$\frac{t}{6} = \frac{1}{2}$

$2t = 6$

$t = \frac{6}{2} = 3$

That is the number of months after April 15, which is 3 months. So July 15.

8 0

3 years ago

What is the value of c?

GaryK [48]

Answer:

180-96 will be the value for c

now do the calculation urself

7 0

3 years ago

In a random sample of 80 teenagers, the average number of texts handled in a day is 50. The 96% confidence interval for the mean

Nastasia [14]

Answer:

a) $\bar X =\frac{46+54}{2}=50$

And the margin of error is given by:

$ME= \frac{54-46}{2}= 4$

The confidence level is 0.96 and the significance level is $\alpha=1-0.96=0.04$ and the value of $\alpha/2 =0.02$ and the margin of error is given by:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

We can calculate the critical value and we got:

$z_{\alpha/2} = 2.05$

And if we solve for the deviation like this:

$\sigma = ME * \frac{\sqrt{n}}{z_{\alpha/2}}$

And replacing we got:

$\sigma =4 *\frac{\sqrt{80}}{2.05} =17.45$

b) $ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}=2.05 *\frac{17.45}{\sqrt{160}}=2.828$

And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor $\sqrt{2}$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma$ represent the population standard deviation

n=80 represent the sample size

Solution to the problem

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

For this case we can calculate the mean like this:

$\bar X =\frac{46+54}{2}=50$

And the margin of error is given by:

$ME= \frac{54-46}{2}= 4$

The confidence level is 0.96 and the significance level is $\alpha=1-0.96=0.04$ and the value of $\alpha/2 =0.02$ and the margin of error is given by:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

We can calculate the critical value and we got:

$z_{\alpha/2} = 2.05$

And if we solve for the deviation like this:

$\sigma = ME * \frac{\sqrt{n}}{z_{\alpha/2}}$

And replacing we got:

$\sigma =4 *\frac{\sqrt{80}}{2.05} =17.45$

Part b

For this case is the sample size is doubled the margin of error would be:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}=2.05 *\frac{17.45}{\sqrt{160}}=2.828$

And as we can see that the margin of error would be lower than the original value of 4, the margin of error would be reduced by a factor $\sqrt{2}$

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2 years ago

Anyone with a knee injury or any doctor! What does it mean if my knee popped locked up all in like 1.5 seconds and then it now h

Dmitry_Shevchenko [17]

Answer:

Knee pain can have causes that aren't due to underlying disease. Examples include heavy physical activity, lack of use, injuries such as sprains or strains, sitting in a constrained area, or sitting on knees for a prolonged period.

Step-by-step explanation:

possibly Chondro malacia

Damage to the cartilage under the kneecap.

Symptoms may include

Knee pain

Cracking joints

Swelling of the knee

Please go to your doctor...ik it hard with cov id and everything

7 0

2 years ago

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