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Andreas93 [3]
3 years ago
5

What is the area of Polygon W?

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
8 0

Answer:

To find the area of a regular polygon, all you have to do is follow this simple formula: area = 1/2 x perimeter x apothem. Here is what it means: Perimeter = the sum of the lengths of all the sides. Apothem = a segment that joins the polygon's center to the midpoint of any side that is perpendicular to that side.

area = n * a * ri / 2 , having ri - incircle radius (it's also an apothem - a line segment from the center to the midpoint of one of its sides) area = perimeter * ri / 2 , given ri and polygon perimeter.

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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
nydimaria [60]

Answer:

352 m^2

Step-by-step explanation:

Each of the four congruent triangular faces has an area that is half the product of the base edge length and the slant height:

A = 1/2·bh = 1/2·(8 m)(22 m) = 88 m^2

Then the total lateral area is 4 times this:

LA = 4·88 m^2 = 352 m^2

6 0
3 years ago
Calculate the circumference of each circle. Round your answer to the nearest hundredth.
lord [1]

Answer: 39.58 cm

Step-by-step explanation:

The circumference of a circle is 2 times  the radius times pi or  pi times the diameter.  so we know the diameter is 12.6 so just multiply it by pie.

12.6 * pi = 39.584

Now rounded to the nearest hundredth is 39.58.

8 0
3 years ago
carmel can drive 320 miles on one tank of gas, and one tankful costs $39. how many tanks of gas will she need to drive 2,240 mil
BARSIC [14]

Answer:

She will need 7 tanks of gas. It will cost $273.

Step-by-step explanation:

First, we divide the amount of miles that she needs to go by the amount she can drive on one tank.

2240/320 = 7

She will need 7 tanks. Multiply the cost of one tank by 7.

$39*7 = $273

It will cost $273 total.

4 0
4 years ago
Please help this is a project.
Aliun [14]

Answer:

What do you need help with, it looks complete to me.

Step-by-step explanation:

8 0
3 years ago
What is the solution of the following equation 2x^2-3x+2=0
zaharov [31]

Answer:

x= \frac{3+\sqrt{7}i}{4}} or x=\frac{3-\sqrt{7}i}{4}}

Step-by-step explanation:

2x^2-3x+2=0

We complete the square as follows

Group the constant term on the right hand side

2x^2-3x=-2

Divide through by 2,

x^2-\frac{3}{2}x=-1

Add half the square of the coefficient of x to get;

x^2-\frac{3}{2}x+(-\frac{3}{4})^2=-1+(-\frac{3}{4})^2

Simplify to get

(x-\frac{3}{4})^2=-1+\frac{9}{16}


(x-\frac{3}{4})^2=-\frac{7}{16}

Take the square root of both sides to get

(x-\frac{3}{4})=\pm \sqrt{-\frac{7}{16}}

Solve for x

(x-\frac{3}{4})=\pm \frac{\sqrt{7}i}{4}}


x=\frac{3}{4} \pm \frac{\sqrt{7}i}{4}}


x= \frac{3+\sqrt{7}i}{4}} or x=\frac{3-\sqrt{7}i}{4}}








6 0
3 years ago
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