Explanation:
Since {v1,...,vp} is linearly dependent, there exist scalars a1,...,ap, with not all of them being 0 such that a1v1+a2v2+...+apvp = 0. Using the linearity of T we have that
a1*T(v1)+a2*T(v1) + ... + ap*T(vp) = T(a1v19+T(a2v2)+...+T(avp) = T(a1v1+a2v2+...+apvp) = T(0) = 0.
Since at least one ai is different from 0, we obtain a non trivial linear combination that eliminates T(v1) , ..., T(vp). That proves that {T(v1) , ..., T(vp)} is a linearly dependent set of W.
The answer to your question is c)15
3 + 2 = 4 + 1 is true
1 +2 = 3 + 3 and 0 + 3 = 3+1 is not true
Answer:
1/96 or 0.01041666667
Step-by-step explanation:
The line segment shown in the figure is C. XZ. A line segment is a line that is bounded by 2 endpoints, hence the line is not infinite. As shown in the figure, only points X and Z are visibly connected. There are no visible lines connecting the other points together.