Answer:
The probability of selecting a non-defective part provided by supplier A is 0.807.
Step-by-step explanation:
Let <em>A</em> = a part is supplied by supplier A, <em>B</em> = a part is supplied by supplier B and <em>D</em> = a part is defective.
<u>Given</u>:
P (D|A) = 0.05, P(D|B) = 0.09
A supplies four times as many parts as B, i.e. n (A) = 4 and n (B) = 1.
Then the probability of event <em>A</em> and <em>B</em> is:

Compute the probability of selecting a defective product:

The probability of selecting a non-defective part provided by supplier A is:

Thus, the probability of selecting a non-defective part provided by supplier A is 0.807.
1.3005 x 10^4
10 to the fourth power
Answer:
PV = 6 and PT = 3
Hope it will help :) see pic ❤
7-5x-(3+5x)
7-5x-3-5x
4-10x
This is my answer☺
1.Do the parenthesis first
2.Combine the like term
The f(9) = 1
first you plug in 9, where x is
f(9) = 2/3(9) - 5
multiply
f(9) = 6 - 5
subtract
and you should get f(9) = 1