<h3>Hello i hope you are having a good day :) Question : Suppose 67% of all teenagers own a laptop and 29% of all teenagers own a laptop and a tablet. What is the probability that a teenager owns a tablet given that the teenager owns a laptop? 19% 38% 43%</h3><h3>Firstly you would do the vent of teenagers that has a laptop would be A) 67% and then the both devices would be B) 29% and then the one with the C) tablet you would do P(CIA) = B/A that would be 29/67 so it would equal 0.43 which means it would be 43 percent. </h3><h3>Hopefully that helps you :)</h3>
Answer:
Step-by-step explanation:
Given:
(segment addition postulate)
(substitution)
(subtracting 17 from each side)
(Subtracting 5y from both sides)
(dividing both sides by -2)
Plug in the value of y
A specific number with a percentage is equal to this number divided by 100 in decimals.
so 89%=89/100 =0.89
Answer:
8/15 is your answer
Step-by-step explanation:
Yes because of the congruent marks