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Artyom0805 [142]
3 years ago
7

Solve. 7w - 12 = 44 w = *

Mathematics
1 answer:
makvit [3.9K]3 years ago
6 0

Answer:

\huge{ \boxed{ \bold{ \text{w = \: 8}}}}

<h3>☃ Question : Solve for w</h3>

\text{7w - 12 = 44 }

<h3>✎ Step by step explanation </h3>

\text{7w - 12 = 44}

Move 12 to right hand side and change it's sign

\longrightarrow{ \sf{7w = 44 + 12}}

Add the numbers : 44 and 12

\longrightarrow{ \sf{7w = 56}}

Divide both sides by 7

\longrightarrow{ \sf{ \frac{7w}{7}  =  \frac{56}{7}}}

\longrightarrow{ \boxed{ \bold{ \red{ \sf{w = 8}}}}}

--------------------------------------------------------------------

☟ Let's check whether the value of w is 8 or not !

<h3>✑ Verification :</h3>

L.H.S ( Left hand side ) :

\dashrightarrow{ \sf{7w - 12}}

plug the value of w and simplify

\dashrightarrow{ \sf{7 \times 8 - 12}}

\dashrightarrow{ \sf{56 - 12}}

\dashrightarrow{ \sf{ 44}}

R.H.S ( Right Hand Side ) = 44

L.H.S = R.H.S ( Hence , the value of w is 8 ).

-----------------------------------------------------------------

<h3>☄ Rules for solving an equation :</h3>
  • If an equation contains fractions , multiply each term by the LCM of denominators.
  • Remove the brackets , if any.
  • Collect the terms with the variable to the left hand side and constant terms to the right hand side by changing their signs ' + ' into ' - ' and ' - ' into ' + ' .
  • Simplify and get the single term on each side.
  • Divide each side by the coefficient of variable and then get the value of variable.

Hope I helped !

Have a wonderful time ! ツ

~ TheAnimeGirl

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These problems are an example of equations with two unknowns. The way these equations are solved is that we write these equations one under the another.

If both equations have, such is the case here, same parts, we can simply cancel the same parts out and subtract the rest of equatuons. That way, we are left with only one unknown (the other one was eliminated), which makes it easy to solve.

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2. Adult ticket costs $12 and child ticket costs $14.

3. Adult ticket costs $10 and child ticket costs $5.

4. One daylily costs $9 and one bush of ornamental grass costs $2.

5. A van can carry 15 and a bus can carry 56 students.

Step-by-step explanation:

2. If we mark the price of one adult ticket with x and the price of one child ticket with y, we get that:

- first day: 7x + 12y = $252

- second day: 7x + 10y = $224

Now, we can make a system:

7x + 12y = 252

7x + 10y = 224

We can now subtract these two equations and 7x will cancel out, so we get:

12y - 10y = 252 - 224

2y = 28

y = 14

Now, we can plug the value of y into any of the two equations:

7x + 10y = 224

7x + 140 = 224

7x = 84

x = 12

3. Similarly, if we mark the price of one adult ticket with x and the price of one child tickey with y, we'll get a system:

x + 12y = 70

x + 9y = 55

Again, if we subtract these two, x will cancel out, so we have:

12y - 9y = 70 - 55

3y = 15

y = 5

Now, we plug the value of y into any of the two equations, and we get:

x + 9y = 55

x + 45 = 55

x = 10

4. Using the same principle, we can mark the price of one daylily with x and the price of one bunch of ornamental grass with y, we'll get a system:

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Again, we subtract so that 12x cancel out and we get:

11y - 12y = 130 - 132

-y = -2

If we get minuses on both sides, we can simply multiply both sides with -1 and we get:

y = 2

Again, we plug y:

12x + 12y = 132

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2x + 12y = 702

2x + y = 86

As you've probably already noticed the pattern, we subtract equations and cancel 2x out to get:

12y - y = 702 - 86

11y = 616

y = 56

Once again, we plug the value of y into any equation:

2x + y = 86

2x + 56 = 86

2x = 30

x = 15

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