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cricket20 [7]
3 years ago
11

I need the answers plz

Mathematics
1 answer:
garik1379 [7]3 years ago
4 0

Answer:

These problems are an example of equations with two unknowns. The way these equations are solved is that we write these equations one under the another.

If both equations have, such is the case here, same parts, we can simply cancel the same parts out and subtract the rest of equatuons. That way, we are left with only one unknown (the other one was eliminated), which makes it easy to solve.

After we have found the value of an unknown, we just plug it back into any of the starting equations and solve for the second unknown.

2. Adult ticket costs $12 and child ticket costs $14.

3. Adult ticket costs $10 and child ticket costs $5.

4. One daylily costs $9 and one bush of ornamental grass costs $2.

5. A van can carry 15 and a bus can carry 56 students.

Step-by-step explanation:

2. If we mark the price of one adult ticket with x and the price of one child ticket with y, we get that:

- first day: 7x + 12y = $252

- second day: 7x + 10y = $224

Now, we can make a system:

7x + 12y = 252

7x + 10y = 224

We can now subtract these two equations and 7x will cancel out, so we get:

12y - 10y = 252 - 224

2y = 28

y = 14

Now, we can plug the value of y into any of the two equations:

7x + 10y = 224

7x + 140 = 224

7x = 84

x = 12

3. Similarly, if we mark the price of one adult ticket with x and the price of one child tickey with y, we'll get a system:

x + 12y = 70

x + 9y = 55

Again, if we subtract these two, x will cancel out, so we have:

12y - 9y = 70 - 55

3y = 15

y = 5

Now, we plug the value of y into any of the two equations, and we get:

x + 9y = 55

x + 45 = 55

x = 10

4. Using the same principle, we can mark the price of one daylily with x and the price of one bunch of ornamental grass with y, we'll get a system:

12x + 11y = 130

12x + 12y = 132

Again, we subtract so that 12x cancel out and we get:

11y - 12y = 130 - 132

-y = -2

If we get minuses on both sides, we can simply multiply both sides with -1 and we get:

y = 2

Again, we plug y:

12x + 12y = 132

12x + 24 = 132

12x = 108

x = 9

5. If we mark number of students in a van with x and the number of students in a bus with y, we get a system:

2x + 12y = 702

2x + y = 86

As you've probably already noticed the pattern, we subtract equations and cancel 2x out to get:

12y - y = 702 - 86

11y = 616

y = 56

Once again, we plug the value of y into any equation:

2x + y = 86

2x + 56 = 86

2x = 30

x = 15

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What is. - 3 7/8 × - 4 3/5 help please
Yakvenalex [24]

Answer:

713/40 or as mixed fraction of 17 33/40 (see setps below)

Step-by-step explanation:

Simplify the following:

-(3 + 7/8) (-(4 + 3/5))

Hint: | Multiply all instances of -1 in -(3 + 7/8) (-(4 + 3/5)).

(-1)^2 = 1:

(4 + 3/5) (3 + 7/8)

Hint: | Put the fractions in 3 + 7/8 over a common denominator.

Put 3 + 7/8 over the common denominator 8. 3 + 7/8 = (8×3)/8 + 7/8:

(4 + 3/5) (8×3)/8 + 7/8

Hint: | Multiply 8 and 3 together.

8×3 = 24:

(4 + 3/5) (24/8 + 7/8)

Hint: | Add the fractions over a common denominator to a single fraction.

24/8 + 7/8 = (24 + 7)/8:

(4 + 3/5) (24 + 7)/8

Hint: | Evaluate 24 + 7 using long addition.

| 1 |  

| 2 | 4

+ | | 7

| 3 | 1:

(4 + 3/5)×31/8

Hint: | Put the fractions in 4 + 3/5 over a common denominator.

Put 4 + 3/5 over the common denominator 5. 4 + 3/5 = (5×4)/5 + 3/5:

31/8 (5×4)/5 + 3/5

Hint: | Multiply 5 and 4 together.

5×4 = 20:

((20/5 + 3/5)×31)/8

Hint: | Add the fractions over a common denominator to a single fraction.

20/5 + 3/5 = (20 + 3)/5:

31/8 (20 + 3)/5

Hint: | Evaluate 20 + 3.

20 + 3 = 23:

23/5×31/8

Hint: | Express 23/5×31/8 as a single fraction.

23/5×31/8 = (23×31)/(5×8):

(23×31)/(5×8)

Hint: | Multiply 5 and 8 together.

5×8 = 40:

(23×31)/40

Hint: | Multiply 23 and 31 together.

| 3 | 1

× | 2 | 3

| 9 | 3

6 | 2 | 0

7 | 1 | 3:

Answer: 713/40

________________________________________

Convert to a mixed number:

713/40

Hint: | Use long division to get a quotient and remainder.

Divide 713 by 40:

4 | 0 | 7 | 1 | 3

Hint: | How many times does 40 go into 71?

40 goes into 71 at most one time:

| | | 1 | |  

4 | 0 | 7 | 1 | 3 |  

| - | 4 | 0 | |  

| | 3 | 1 | 3 |  

Hint: | How many times does 40 go into 313?

40 goes into 313 at most 7 times:

| | | 1 | 7 |  

4 | 0 | 7 | 1 | 3 |  

| - | 4 | 0 | |  

| | 3 | 1 | 3 |  

| - | 2 | 8 | 0 |  

| | | 3 | 3 |  

Hint: | Summarize the results.

Read off the results. The quotient is the number at the top and the remainder is the number at the bottom:

| | | 1 | 7 | (quotient)

4 | 0 | 7 | 1 | 3 |  

| - | 4 | 0 | |  

| | 3 | 1 | 3 |  

| - | 2 | 8 | 0 |  

| | | 3 | 3 | (remainder)

Hint: | In the equivalent mixed fraction, the quotient becomes the whole number part, the remainder becomes the numerator part, and the divisor (denominator) remains the denominator.

The quotient of 713/40 is 17 with remainder 33, so:

Answer: 17 33/40

6 0
3 years ago
Brainliest, but dont darn answer IF YOUR NOT GOING TO EXPLAIN HOW YOU GET YOUR ANSWER, please and thanks, appreciate ya!
stich3 [128]

Answer:

A. 2/3

Step-by-step explanation:

Simplify it by four, 8 / 4 = 2, 12 / 4 = 3

3 0
2 years ago
Read 2 more answers
What is the area of the squares with sides (2x-3)feet?​
LUCKY_DIMON [66]

Answer:

4x^2 -12x +9   ft^2

Step-by-step explanation:

The area of a square is

A = s^2 where s is the side length

A = (2x-3) ^2

A = (2x-3) (2x-3)

FOIL

first 2x*2x =4x^2

outer 2x (-3) = -6x

inner -3*2x = -6x

last -3*-3 = 9

Add them together

4x^2 -6x-6x +9

Combine like terms

4x^2 -12x +9

The area is 4x^2 -12x +9 ft^2

5 0
3 years ago
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What is the area of the parllelogtam shown below
Umnica [9.8K]
<h3>Answer: 16 square units</h3>

Let x be the height of the parallelogram. Right now it's unknown, but we can solve for it using the pythagorean theorem. Focus on the right triangle. It has legs a = 3 and b = x, with hypotenuse c = 5

a^2 + b^2 = c^2

3^2 + x^2 = 5^2

9 + x^2 = 25

x^2 = 25-9

x^2 = 16

x = sqrt(16)

x = 4

This is a 3-4-5 right triangle.

The height of the parallelogram is 4 units.

We have enough info to find the area of the parallelogram

Area of parallelogram = base*height

Area of parallelogram = 4*4

Area of parallelogram = 16 square units

Coincidentally, the base and height are the same, which isn't always going to be the case. The base is visually shown as the '4' in the diagram. The height is the dashed line, which also happens to be 4 units long.

6 0
3 years ago
What is the square root of 683
Mashutka [201]

Answer:

The square root of six hundred and eighty-three √683 = 26.13426869074



4 0
3 years ago
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