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yan [13]
3 years ago
6

Mr. Jamison, an art teacher, would like to purchase enough supplies to get the class stocked. He picks up 8 dozen sketch pencils

, 6 dozen colored pencils, and 3 dozen art gum erasers. If the sales tax rate is 8%, approximately what will his bill be?
Advanced Placement (AP)
2 answers:
MatroZZZ [7]3 years ago
7 0

Answer:

Answer is 48

Explanation:

padilas [110]3 years ago
4 0
His bill will be approximately 48:)
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What was one important academic skill the blogger learned?
Angelina_Jolie [31]

Answer:

An academic skill that the blogger learned, was to review the graded tests and quizzes to see which concepts he missed out on so that in the future he would be well prepared for it. Reviewing and comparing the tests and quizzes would give him an idea on which topics he needs to study.

Explanation:

3 0
3 years ago
Describe motivations for settling in the Massachusetts Bay colony
ss7ja [257]
Well the Massachusetts Bay colony was settled by Puritans as you probably know and their reason was religious reasons. I’m sorry I don’t have any more details, hoped this helped!
8 0
3 years ago
The regions bounded by the graphs of y=x2 and y=sin2x are shaded in the figure above. What is the sum of the areas of the shaded
Alex Ar [27]

Answer:

The sum of the area of the shaded regions = 0.248685

Explanation:

The sum of the area of the shaded region is given as follows;

The point of intersection of the graphs are;

y = x/2

y = sin²x

∴ At the intersection, x/2 = sin²x

sinx = √(x/2)

Using Microsoft Excel, or Wolfram Alpha, we have that the possible solutions to the above equation are;

x = 0, x ≈ 0.55 or x ≈ 1.85

The area under the line y = x/2, between the points x = 0 and x ≈ 0.55, A₁, is given as follows

1/2 × (0.55)×0.55/2 ≈ 0.075625

The area under the line y = sin²x, between the points x = 0 and x ≈ 0.55, A₂, is given using as follows;

\int\limits {sin^n(x)} \, dx = -\dfrac{1}{n} sin^{n-1}(x) \cdot cos(x) + \dfrac{n-1}{n} \int\limits {sin^{n-2}(x)} \, dx

Therefore;

A_2 = \int\limits^{0.55}_0 {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_0 ^{0.55}

∴ A₂ =1/2 × ((0.55 - sin(0.55)×cos(0.55)) - (0 - sin(0)×cos(0)) ≈ 0.0522

The shaded area, A_{1 shaded} = A₁ - A₂ = 0.075625 - 0.0522 ≈ 0.023425

Similarly, we have, between points 0.55 and 1.85

A₃ = 1/2 × (1.85 - 0.55) × 1/2 × (1.85 - 0.55) + (1.85 - 0.55) × 0.55/2 = 0.78

For y = sin²x, we have;

A_4 = \int\limits^{1.85}_{0.55} {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_{0.55} ^{1.85} \approx 1.00526

The shaded area, A_{2 shaded} = A₄ - A₃ = 1.00526 - 0.78 ≈ 0.22526

The sum of the area of the shaded regions, ∑A = A_{1 shaded} + A_{2 shaded}

∴ A = 0.023425 + 0.22526 = 0.248685

The sum of the area of the shaded regions, ∑A = 0.248685

8 0
3 years ago
Please help this is due tn and i don’t really get what’s it’s asking if u could just tell me the answers please
Gnesinka [82]

Answer:

try asking your teacher

3 0
3 years ago
What was most likely the cause for the change between 1990 and 2013 in the East Asia and Pacific region?
nordsb [41]

Answer:

Option B, China experienced rapid industrial and urban population growth

Explanation:

In the East Asian region, China grew very fast in terms of industrialization and hence the urban cities and population in it. These two factors contributed tremendously in the increase of GDP of the China individually and as well as the entire region.

China emerged as the manufacturing hub of the world and became a global supporter of all major business across the globes.

Hence, option B is correct

7 0
2 years ago
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