2t/5=8t/20 (both numbers multiplied by 4)
t/4=5t/20 (both numbers multiplied by 5)
3=60/20
⇒ 8t/20 - 5t/20= 60/20
3t/20=60/20
⇒3t=60
t=60:3
t=20
I hope you understand !
Answer:
Step-by-step explanation:
What is the cube root of 
? This is the question.
We can write:
![\sqrt[3]{27a^{12}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E%7B12%7D%7D)
We will use the below property to simplify:
![\sqrt[n]{a*b}=\sqrt[n]{a} \sqrt[n]{b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%2Ab%7D%3D%5Csqrt%5Bn%5D%7Ba%7D%20%20%5Csqrt%5Bn%5D%7Bb%7D)
So, we have:
![\sqrt[3]{27a^{12}} =\sqrt[3]{27} \sqrt[3]{a^{12}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E%7B12%7D%7D%20%3D%5Csqrt%5B3%5D%7B27%7D%20%5Csqrt%5B3%5D%7Ba%5E%7B12%7D%7D)
We will now use below property to further simplify:
![\sqrt[n]{x} =x^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%20%3Dx%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Thus, we have:
![\sqrt[3]{27} \sqrt[3]{a^{12}} =3*(a^{12})^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%20%5Csqrt%5B3%5D%7Ba%5E%7B12%7D%7D%20%3D3%2A%28a%5E%7B12%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
We know power to the power rule: 
Now, we have:
This is the correct answer:
Answer:
5x - 4y = 0
Step-by-step explanation:
the equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
given 0 = - 5x + 4y ( multiply through by - 1 )
5x - 4y = 0 ← in standard form
Answer:
-31 is the answer
Step-by-step explanation:
B) 1.6^4 1.6 is being multiplied 4 times
