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Nikolay [14]
3 years ago
14

Is Figure B a scale copy of Figure A? Choose 1 answer: A. Yes B. No

Mathematics
2 answers:
Nataliya [291]3 years ago
8 0

Answer:

A Yes

Step-by-step explanation:

the ratio is 2:1

algol [13]3 years ago
3 0

Answer:

A. yes

Step-by-step explanation:

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PLEASEEEE ANSWERRRR!!!!!!<br> Find the area of the shape shown below.
astra-53 [7]

Step-by-step explanation:

This is the answer. Hope it helps.

8 0
3 years ago
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Evaluate b^2 for b= -4
tekilochka [14]

Answer:

16

Step-by-step explanation:

b^2

Let b= -4

(-4)^2

16

5 0
3 years ago
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b) How many ways can you deal cards (from a deck of 52) to 4 people when each player gets 7 cards. 2 hidden and 5 visible. Assum
Mariana [72]

Answer:

{52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

Step-by-step explanation:

The dealing of the cards can be seen in the following way:

We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in {52 \choose 7} ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in {7 \choose 2} ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in {45 \choose 7}. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in {7 \choose 2} ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in {38 \choose 7}. And again, we have to choose which ones are the hidden ones, which can be chosen in {7 \choose 2} ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in {31 \choose 7} ways. And choosing which ones are the hidden ones for this player can be done in {7 \choose 2} ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

{52 \choose 7}{7 \choose 2}{45 \choose 7}{7 \choose 2}{38 \choose 7}{7 \choose 2}{31 \choose 7}{7 \choose 2}={52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

7 0
3 years ago
I attached an image. someone help me asap. i'm not the smartest person so i cont understand it :(
vampirchik [111]

Answer:

for the second column it is 12.5

for the third column it is 20%

for the fourth column it is 120%

for the fifth column it is 33%

for the sixth column it is 11.35

for the seventh column it is 900

for the 8th column it is 60%

for the final column it's 39

Step-by-step explanation:

7 0
2 years ago
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Find the volume of the cone
Anuta_ua [19.1K]

Volume= 37. 7

V=π r² h/3 = π · 22 · 9/3 ≈37.69911

I hope this helps!

8 0
3 years ago
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