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vitfil [10]
2 years ago
8

Someone help me with this!!!!! ASAP

Mathematics
1 answer:
san4es73 [151]2 years ago
3 0

here's the solution,

let <u>the segment be AB</u>, and PQ is perpendicular bisector of AB at Q , and Let P be the point on perpendicular bisector, and join P with A and B,

and since <u>PQ bisects AB into AQ</u> and BQ, they are equal,

that is , AQ = BQ

now, two triangles are formed.

In the given triangles, <u>PQA and PQB</u>

  • PQ = PQ

( common side )

  • mPQA = mPQB

( perpendicular forms 90° )

  • AQ = BQ

( they are equal, proved above )

here, Triangle PQA and PQB are congruent by SAS ( side angle side ) criterion.

So, AP = BP ( by C.P.C.T )

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