Answer:
For a trapezium of height H, parallel side 1 X, and parallel side 2 Y, the area is:
A = (1/2)*H*(X + Y)
with this we can complete the table.
a)
Here we know:
X = 7cm
Y = 11cm
H = 6cm
Then: A = (1/2)*6cm*(7cm + 11cm) = 54 cm^2
b)
Here we know:
X = 8 m
Y = 10 m
A = 126 m^2
Then:
126 m^2 = 0.5*H*(8m + 10m)
126 m^2 = H*9m
126 m^2/9m = H = 14m
Then the height of this trapezoid is 14m
c)
Here we know:
X = 5mm
H = 8mm
A = 72 mm^2
Then:
72 mm^2 = 0.5*8mm*(5mm + Y)
72 mm^2 = 4mm*(5mm + Y)
72mm^2/4mm = 5mm + Y
18 mm = 5mm + Y
18mm - 5mm = Y
13 mm = Y
Then the parallel side 2 is 13 mm long.
Answer:
i believe it would be $443.75
Step-by-step explanation:
just add 8.75 to 9.00 then multiply it by 25
8.75+9.00= 17.75 x 25= 443.75
if its a different type of equation then maybe this didn't help but i hope it does
They practiced 35 minutes longer on the second day.
Answer:
5.5 or simply 6
Step-by-step explanation:
6 = 33
1 = x
6x = 33
x = 5.5 ~6
Answer:
Acute.
Step-by-step explanation:
Using the Triangle Inequality Theorem you know that the sum of the lengths of two sides of a triangle are greater than the length of the third side.
Using this we can narrow it down that this DOES have a solution, since 10+12>15.
Now, we can determine if this triangle is a right triangle using the Pythagorean Theorem. C is the longest length.
If c^2= a^2+b^2, then it is a right triangle.
If c^2< a^2+b^2 then it is an acute triangle.
If c^2>a^2+b^2 then it is an obtuse triangle.
We can now substitute. (A and B are interchangeable, but C is the longest length.
A=10
B=12
C=15
A^2=100
B^2=144
C^2=255
We can now figure out that this triangle is acute because A^2+ B^2 (244) < C^2 (255).
Hope this helps!
