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aliya0001 [1]
3 years ago
13

Suppose 2 circles are constructed. Under what conditions do the circles have 1 point in common, 2 points in common, no points in

common, more than two points in common?
Mathematics
1 answer:
sineoko [7]3 years ago
5 0
If the two circles are touching tangentially at one point then they have one point in common.  If centers are C1 & C2 and radii are R1 & R2. then  if distance C1C2 = R1+R2 then they have one point in common.


if 0< C1C2  < R1+R2  they are two points in common.
if C1C2 = 0  R1 = R2  then they have all the points in common. they are the same circle.
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A student is trying to solve the system of two equations given below: Equation P: a + b = 6 Equation Q: 4a + 2b = 19 Which of th
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Answer:

-4(a + b = 6)

Step-by-step explanation:

Given

a + b = 6

4a + 2b = 19

Required

Eliminate a

Multiply the first equation by -4

-4(a + b = 6)

Add to the second equation

-4(a + b = 6) + (4a + 2b = 19)

Solve brackets

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Open bracket

-4a + 4a -4b  + 2b = -24 + 19

-4b  + 2b = -24 + 19

At this point, a has been eliminated;

From the list of given options, the option that answers the question is -4(a + b = 6)

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Which tools can be used for inductive reasoning?
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solniwko [45]

Answer:

The total surface area of all 6 prisms is 6336 in^2.

Step-by-step explanation:

Let's find the surface area of ONE prism and then multiply that result by 6 to obtain the final answer.

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The total surface area of ONE prism is thus:

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Now, because there are 6 of these prisms, multiply this last result by 6:

6(1056 in^2) = 6336 in^2.

The total surface area of all 6 prisms is 6336 in^2.

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