3 = 4 - 4^0 * 4/4
4 = 4^0 + 4^0 + 4^0 + 4^0
5 = 4^2 / (4^0 * 4) + 4^0
6 = 4^2 / 4 + 4^0 + 4^0
Answer:
LHS.= Sin 2x /( 1 + cos2x )
We have , sin 2x = 2 sinx•cosx
And. cos2x = 2cos^2 x - 1
i.e . 1+ cosx 2x = 2cos^2x
Putting the above results in the LHSwe get,
Sin2x/ ( 1+ cos2x ) =2 sinx•cosx/2cos^2x
=sinx / cosx
= Tanx
.•. sin2x/(1 + cos2x)= tanx
Step-by-step explanation:
Answer:
9 tiles needed to fill
Step-by-step explanation:
16 - 7
Least common multiple: factor them, then see what they have in common and what is leftover and multiply those expressions:
(x - 2)(x + 3) 10(x + 3)(x + 3)
Common: (x + 3)
Leftover: (x - 2), (10), (x + 3)
Common · Leftover is: (x + 3) · (x - 2) · (10) · (x + 3) = 10(x - 2)(x + 3)²
Answer: LCM is 10(x - 2)(x + 3)²
Answer:
R=2
Step-by-step explanation:
2x2=4