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kakasveta [241]
3 years ago
14

Which equation represents a line which is perpendicular to the line y= –1/8x + 8

Mathematics
1 answer:
Zigmanuir [339]3 years ago
8 0
The answer to you equation is Y=63/8
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How to work scientific notation
Feliz [49]
It like instead of saying 0.0000056 you can write it in a shorter form like          5.6 * 10-6.Its like moving the decimal point between 5 and 6 and multiplying it by the power 10*6. its like how much time you move the decimal point, it will be how much time you say 10 to the power of how much you move it.

5 0
3 years ago
Need help with problem #53! Arithmetic sequences!
ankoles [38]

When counting any sequence, it helps to have a simpler sequence to compare it to. The simplest one that I can think of is

1,2,3,4,5,\dots

because you instantly can tell the number of terms in the sequence by looking at the last number. We can see from the graph that the first few terms of the sequence a are 1, -3, -7, and we're told that its last term is -83. Our goal then is to turn this sequence:

1,-3,-7,\dots,-83

into this one:

1,2,3,\dots

The first thing which stands out in this sequence is the number of negative terms, so let's fix that by multiplying every term by -1:

1,-3,-7,\dots,-83\xrightarrow{\times{-1}}-1,3,7,\dots,83

Now, the main property of any arithmetic sequence is that they <em>increase or decrease by some constant amount</em>. Here, that number is 4, since -3 = 1 - 4 and -7 = -3 - 4. Knowing the importance of 4 in this sequence, our next step might be to turn every term into a multiple of 4 by adding 1:

-1,3,7,\dots,83\xrightarrow{+1}0,4,8,\dots,84

and since we're dealing with multiples of 4, a natural next step might be to divide every term by 4:

0,4,8,\dots,84\xrightarrow{\div4}0,1,2,\dots,21

And lastly, we can add 1 to every term to get our sequence into easily-countable form:

0,1,2,\dots,21\xrightarrow{+1}1,2,3,\dots,22

So, the sequence a has 22 terms.

8 0
4 years ago
How many 3 letter codes are possible using a-j without repeats?
Dennis_Churaev [7]
There are 10 letters in the set {a, b, c, d, e, f, g, h, i, j} which is the pool of letters to choose from when making these three letter codes.

We have 10 choices for slot 1
Then 9 choices for slot 2. This is because we can't reuse the choice for slot 1
Then 8 choices for slot 3

Overall, there are 10*9*8 = 90*8 = 720 different permutations

Answer: 720

Note: you can use the nPr permutation formula with n = 10 and r = 3 to get the same answer
5 0
3 years ago
Someone please helppppp!
zloy xaker [14]

Answer:

AB=24.5

Step-by-step explanation:

5x+7=7x

7=2x

x=3.5

7(3.5)=24.5

6 0
3 years ago
1. Mr. Xavier took his 18 students and 9 other chaperones to an amusement
Advocard [28]
The answer is D. For Mrs Yadira's class there are 11s 4c and 489 in total.
7 0
3 years ago
Read 2 more answers
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