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4vir4ik [10]
3 years ago
14

A cake pan in the shape of a right triangle is shown below. What is the volume of the open area of the cake pan? A. 90 cubic inc

hes B. 45 cubic inches C. 120 cubic inches D. 180 cubic inches

Mathematics
2 answers:
leonid [27]3 years ago
8 0

Answer:

D. 180

Step-by-step explanation: multiply

densk [106]3 years ago
6 0

Answer:

Im pretty sure its d

Step-by-step explanation:

im not sure but i’m sorry if its wrong

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1. The minimum head breadth that will fit the clientele is of 3.95-in.

2. The maximum head breadth that will fit the clientele is of 9.25-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 6.6-in and a standard deviation of 1.1-in.

This means that \mu = 6.6, \sigma = 1.1

1. What is the minimum head breadth that will fit the clientele?

The 0.8th percentile, which is X when Z has a p-value of 0.008, so X when Z = -2.41.

Z = \frac{X - \mu}{\sigma}

-2.41 = \frac{X - 6.6}{1.1}

X - 6.6 = -2.41*1.1

X = 3.95

The minimum head breadth that will fit the clientele is of 3.95-in.

2. What is the maximum head breadth that will fit the clientele?

The 100 - 0.8 = 99.2nd percentile, which is X when Z has a p-value of 0.992, so X when Z = 2.41.

Z = \frac{X - \mu}{\sigma}

2.41 = \frac{X - 6.6}{1.1}

X - 6.6 = 2.41*1.1

X = 9.25

The maximum head breadth that will fit the clientele is of 9.25-in.

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Step 1: Add the two equations.

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