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ankoles [38]
3 years ago
10

Can u help me pls This homework was due last week I really need help thx xxx

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
4 0
The ratio of squash to water is 2:7
Ivenika [448]3 years ago
3 0

Answer:

2:7 I believe the answer is

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Look at the function below.
weqwewe [10]
The answer is B because the x describes the domain and it can also be the input value
4 0
3 years ago
Write in point slope form an equation of the line that passes through the given point and has the given slope: (0,1); m= 2
sergey [27]

           - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

\diamond\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}\diamond

         Write an equation for the line that passes through (0, 1) and has a slope of 2 (in point-slope form).

\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}\diamond

<u>Point-slope form</u>:-

      \sf{y-y_1=m(x-x_1)}

Substitute 1 for y₁, 2 for m, and 0 for x₁:-

\sf{y-1=2(x-0)}

So we conclude that Option B is correct.

<h3>Good luck.</h3>

            - - - - - -  - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

3 0
2 years ago
Mark ran 875 miles this year in the track club.Mark ran in 52 track meets and ran the same number of miles in each.How many mile
shepuryov [24]

Answer:

The number of miles Mark runs in each track be 16 \frac{43}{52}\ miles

Step-by-step explanation:

Let us assume that the number of miles Mark run in each track meet be x.

As given

Mark ran 875 miles this year in the track club.

Mark ran in 52 track meets and ran the same number of miles in each.

Than the equation becomes

52 × x = 875

x = \frac{875}{52}

x = 16 \frac{43}{52}\ miles

Therefore the number of miles Mark runs in each track be 16 \frac{43}{52}\ miles

7 0
3 years ago
Help needed asap !!!!!!
Zinaida [17]

Answer:

b)0, yes

Step-by-step explanation:

Given:

Vectors (4,8) . (6,-3)

Finding inner product of vectors:

= 4x6 + 8x-3

=24-24

=0

Now to check the angle between them using formula a.b=|a|.|b|cosθ

|a|= \sqrt{4^{2} +8^{2} } \\\sqrt{16+64}

   =8.9

|b|=\sqrt{6^{2} +(-3)^{2} } \\\sqrt{36+9}

   =6.7

Putting values of a.b=0 and |a|=8.9, |b|=6.7 in a.b=|a|.|b|cosθ we get,

0= 8.9(6.7)cosθ

cosθ =0

θ=90 degrees

Hence the two vectors are perpendicular !

7 0
3 years ago
In the diagram A, B, and C are the points on the circle. Use the diagram to prove the theorem which states that:
nevsk [136]

9514 1404 393

Explanation:

Here's one way to go at it.

Draw segments AB and CO. Define angles as follows. (The triangles with sides that are radii are all isosceles, so their base angles are congruent.)

  x = angle OAB = angle OBA

  y = angle OAC = angle OCA

  z = angle OBC = angle OCB

Consider the angles at each of the points A, B, C.

At A, we have ...

  angle CAB = x + y

At B, we have ...

  angle CBA = x + z

At C, we have ...

  angle ACB = y + z

The sum of the angles of triangle ABC is 180°, as is the sum of angles in triangle ABO. This gives ...

  x + x + ∠AOB = (x+y) +(x+z) +(y+z)

  ∠AOB = 2(y+z) = 2∠ACB

This shows ∠AOB = 2×∠C, as required.

8 0
3 years ago
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