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viva [34]
2 years ago
8

The Collatz conjecture is one of the most famous unsolved mathematical problems, because it's so simple, you can explain it to a

primary-school-aged kid, and they'll probably be intrigued enough to try and find the answer for themselves.
Mathematics
1 answer:
Vinil7 [7]2 years ago
6 0

Hi, you've asked an incomplete question. However, I inferred you need a brief explanation about The Collatz conjecture.

<u>Explanation:</u>

Put simply, what the Collatz conjecture unsolved problem entails is that if any positive number is picked and it is:

  1. An even number (eg 2, 4, 6,...), then if they are divided by 2,  the new number gotten should undergo the same process (that is to be divided by 2), it is believed your calculation would finally end up at 1. For example, let's pick the number 6, (6÷2=4; repeating the process 4÷2=<u>1</u>)
  2. An odd number, then if they are multiplied by 3 and 1 is added to the result, it is believed that your calculation would finally end up at 1.
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RSB [31]

Answer:

its 7

Step-by-step explanation:

3 0
3 years ago
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Perform the indicated row operations, then write the new matrix.
Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]

Operations:

2R_1 + R_2 ->R_2

-3R_1 +R_3 ->R_3

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]

Step-by-step explanation:

The first operation:

2R_1 + R_2 ->R_2

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]

Multiply by 2

2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]

Add to row 2 elements are: \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]

\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]

\left[\begin{array}{ccc}0&5&7|1\end{array}\right]

The second operation:

-3R_1 +R_3 ->R_3

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]

Multiply by -3

-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]

Add to row 2 elements are: \left[\begin{array}{ccc}3&2&4|1\end{array}\right]

\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]

\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]

Hence, the new matrix is:

\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]

3 0
3 years ago
Read 2 more answers
I need answer and work to please and thanks
Sergeu [11.5K]
Sorry i dont know this answer

3 0
3 years ago
6 2/5 x 1 7/8 x 7/12=
andrey2020 [161]

7 the awnser is 7 ok(kkkkk

3 0
2 years ago
Josie is training for a race the ratio of the number of minutes she wants to the number of miles she wants is 2043 she plans to
guajiro [1.7K]

Answer:

Josie takes 0.93 minutes to run 2 miles.

Step-by-step explanation:

We are given the following in the question:

Ratio:

Number of minutes: Number of miles = 20:43

Josie wants to run 2 miles. We have to find the number of minutes she need to run to maintain the ration.

Let x be the number of minutes Josie run.

This can be done in the following manner:

\dfrac{20}{43} = \dfrac{x}{2}\\\\\Rightarrow x = \dfrac{20}{43}\times 2\\\\\Rightarrow x = 0.93

Thus, Josie takes 0.93 minutes to run 2 miles.

8 0
3 years ago
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