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3 years ago

11

Best buy sells iPhones amd Samsung. Thy have 81 phones in the store. If the number of iphones is twice the number of Samsung's h

ow many of each phone does the story carry?

1 answer:

seropon [69]3 years ago

5 0

Answer:

54 iphones ,27 samsungs

81/3=27

27x2=54

81-54=27

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Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

3 years ago

There are 45 students in a class. The ratio of boys to girls is 2:3. How many boys are there in the class?

Lena [83]

Answer:

18 boys

Step-by-step explanation:

we add 2 and 3 because they are equal parts:

2+3=5

Then we divide 45 by 5 because we want to find what 1 part equals"

45/5=9

We now do 9*2 to get an answer of:

9*2=18

hope this makes sense!

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3 years ago

$23 marked down by 15%.

DanielleElmas [232]

Answer:

7

Step-by-step explanation:

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3 years ago

What is the simplified form of the expression?

AleksAgata [21]

The answer is: 10 x¹³ y¹⁰ .
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1x^8 * 2y^(10) * 5x^5 =

1* 2* 5 * x^8 * x^5 * y^(10) =

10 * x^(8+5) * y^(10) =

10 * x^(13) * y^(10) = 10 x^(13) y^10 ; write as:
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10 x¹³ y¹<span>⁰ .
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4 years ago

I need help with these

rewona [7]

Also 8 i believe not sure though

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3 years ago