BRAINIEST AND 15 POINTS HELP FAST!!!
1 answer:
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Area of ABC : AB*AC/2
the maximum of the parabola is reached at x=-4/(2*(-1))=2 hence A is at (2,0) and B is at (2,(-2)^2+4*2+C)=(2,12+C)
C is the second root (x-intersect), which we can find :
determinant1 : D=16-4*(-1)*C=4(4+C) thus the second root is at x=
Hence the area of the triangle is
hence 
.
We remark that
Hence 4+C=16 thus C=12
the maximum of the parabola is reached at x=-4/(2*(-1))=2 hence A is at (2,0) and B is at (2,(-2)^2+4*2+C)=(2,12+C)
C is the second root (x-intersect), which we can find :
determinant1 : D=16-4*(-1)*C=4(4+C) thus the second root is at x=
Hence the area of the triangle is
We remark that
Hence 4+C=16 thus C=12
Answer:
(4, 7 )
Step-by-step explanation:
y = 3x - 5 → (1)
y = x + 5 ( multiply through by 2 to clear the fraction )
2y = x + 10 → (2)
Substitute y = 3x - 5 into (2)
2(3x - 5) = x + 10 ← distribute parenthesis on left side
6x - 10 = x + 10 ( subtract x from both sides )
5x - 10 = 10 ( add 10 to both sides )
5x = 20 ( divide both sides by 5 )
x = 4
Substitute x = 4 into (1) and evaluate for y
y = 3(4) - 5 = 12 - 5 = 7
solution is (4, 7 )