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tresset_1 [31]
3 years ago
15

Help me please and thank you

Mathematics
1 answer:
Komok [63]3 years ago
6 0

Answer:

qwertyuiopasdfhjklxcvbnm

xfghijguvm,

rk3hjktnevmlegkp3q

Step-by-step explanation:

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Answer:

C. z = 2.05

Step-by-step explanation:

We have to calculate the test statistic for a test for the diference between proportions.

The sample 1 (year 1995), of size n1=4276 has a proportion of p1=0.384.

p_1=X_1/n_1=1642/4276=0.384

The sample 2 (year 2010), of size n2=3908 has a proportion of p2=0.3621.

p_2=X_2/n_2=1415/3908=0.3621

The difference between proportions is (p1-p2)=0.0219.

p_d=p_1-p_2=0.384-0.3621=0.0219

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{1642+1415}{4276+3908}=\dfrac{3057}{8184}=0.3735

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.3735*0.6265}{4276}+\dfrac{0.3735*0.6265}{3908}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00006}=\sqrt{0.00011}=0.0107

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.0219-0}{0.0107}=\dfrac{0.0219}{0.0107}=2.05

z=2.05

4 0
3 years ago
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