Answer:
There is no point of the form (-1, y) on the curve where the tangent is horizontal
Step-by-step explanation:
Notice that when x = - 1. then dy/dx becomes:
dy/dx= (y+2) / (2y+1)
therefore, to request that the tangent is horizontal we ask for the y values that make dy/dx equal to ZERO:
0 = ( y + 2) / (2 y + 1)
And we obtain y = -2 as the answer.
But if we try the point (-1, -2) in the original equation, we find that it DOESN'T belong to the curve because it doesn't satisfy the equation as shown below:
(-1)^2 + (-2)^2 - (-1)*(-2) - 5 = 1 + 4 + 2 - 5 = 2 (instead of zero)
Then, we conclude that there is no horizontal tangent to the curve for x = -1.
I hope this helps you
area formula=pi.r^2
1) Area=3,14. (3,5)^2
Area=38,465
Area nearest 38,5
2) Circumference=2pi.r
Circumference=2.3,14.3,5
Circumference=21,98
Circumference nearest 22
Well, 7 times 5 is 35 so if that's the case there's your answer.
Please help!
Remember what we know about vertical angles and solve for x.
Answer:
A.
If you roll up the quarter circle and cap the open end with the smaller circle, the resulting shape should be a cone.
