Ask question

Ask question

All categories

3 years ago

5

Which transformations can be used to map a triangle with vertices A (2, 2), B (4, 1), C (4, 5) to A’ (–2, –2), B’ (–1, –4), C’ (

–5, –4)?
a
a 90 degree clockwise rotation about the origin and a reflection over the y-axis

b
a 90 degree counterclockwise rotation about the origin and a translation down 4 units

c
a 180 degree rotation about the origin

d
a reflection over the y-axis and then a 90 degree clockwise rotation about the origin

1 answer:

Aliun [14]3 years ago

6 0

A is the the answer for you

You might be interested in

11 identical pairs of Air Jordan cost $660.What is the cost of one pair?

Crank

Answer:

$60

Step-by-step explanation:

11 identical pairs of Air Jordan cost $660.

To find the cost of one pair, you have simply to divide the total amount paid by the total number of pairs.

Total amount paid = $660

Total number of pairs = 11

The cost of one pair $=\$660 : 11=\$60$

6 0

3 years ago

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

2 years ago

Explain why any of the four operations (+x +) placed between the two terms 5 and-3/(radical sign) 8 will result in an irrational

kompoz [17]

To answer this question we will have to understand the nature of $\sqrt{8}$ .

$\sqrt{8}$ can be rewritten as: $\sqrt{2\times 2\times 2} =2\sqrt{2}$ . Now, $\sqrt{2}$ is an irrational number and thus any of the four operations of addition, multiplication, subtraction or division placed anywhere between any of these terms will always result in an irrational number.

The only way irrational numbers can be made rational is by dividing or multiplying the given irrational number by the same irrational number.

8 0

2 years ago

HELP ASAP WILL MARK BRAINLIEST

DochEvi [55]

Answer:

EF , HG , Parallel

Step-by-step explanation:

Here we are given a translated quadrilateral EFGH from Quadrilateral ABCD.

Also given that AB was parallel to DC.

Now we have to fill in the certain blanks.

Here EF is parallel to AB , As EFGH is a translated image of ABCD. And EF and AB are the corresponding sides.

Also HG is parallel to DC, EFGH is a translated image of ABCD.

Also we are given that AB is parallel to DC. Hence we have following results.

AB║DC

AB║EF

Hence CD║EF

also

CD ║HG

CD║EF

Hence we can come to conclusion that

EF║HG

Hence our answer will be

corresponding segments EF and HG are parallel to each other.

3 0

3 years ago

What is the center and radius of the circle that has the equation x+72+y-42=49? Explain.

balu736 [363]

Answer: The center is (-7, 4) and the radius is 7.

Step-by-step explanation:

The equation for a circle usually is:

(x - a)^2 + (y - b)^2 = R^2

where R is the radius, and (a, b) is the center of the circle.

I guess that the equation in this case is:

(x + 7)^2 + (y - 4)^2 = 49

then, in this case we have:

a = -7 and b = 4, then (a, b) = (-7, 4)

this means that the center of our circle is in the point (-7, 4)

and we know that:

R^2 = 49

R = √49 = 7

Then the radius is equal to 7.

3 0

3 years ago