Answer:
254.47 m or B
Step-by-step explanation:
First you find the area of the circle and then you subtract it from the area of the square to get your answer.
Hope it helps c:
Answer:
81.76in^2
Step-by-step explanation:
Given data
Lenght of book= 11.2 inches
WIdth of book= 7.3 inches
We know that Area= Length* Width
Area= 11.2*7.3
Area= 81.76 in^2
Hence the area of the front of the book is is 81.76in^2
i can help if you have the picture
Answer:
m∠FEH = 44°
m∠EHG = 64°
Step-by-step explanation:
1) The given information are;
The angle of arc m∠FEH = 272°, the measured angle of ∠EFG = 116°
Given that m∠FEH = 272°, therefore, arc ∠HGF = 360 - 272 = 88°
Therefore, angle subtended by arc ∠HGF at the center = 88°
The angle subtended by arc ∠HGF at the circumference = m∠FEH
∴ m∠FEH = 88°/2 = 44° (Angle subtended at the center = 2×angle subtended at the circumference)
m∠FEH = 44°
2) Similarly, m∠HGF is subtended by arc m FEH, therefore, m∠HGF = (arc m FEH)/2 = 272°/2 = 136°
The sum of angles in a quadrilateral = 360°
Therefore;
m∠FEH + m∠HGF + m∠EFG + m∠EHG = 360° (The sum of angles in a quadrilateral EFGH)
m∠EHG = 360° - (m∠FEH + m∠HGF + m∠EFG) = 360 - (44 + 136 + 116) = 64°
m∠EHG = 64°.
Answer:
(f+g)(x)=x^2+8+x-2
=x^2+x+6
The answer is the 3rd one in your options.
