An urn contains seven red and five white balls. Four balls are randomly drawn from the urn in succession with replacement. That
1 answer:
Complete Question:
An urn contains seven red and five white balls. Four balls are randomly drawn from the urn in succession with replacement. That is after each drawn the selected ball is returned to the urn. What is the probability that four balls drawn from the urn are white?
Answer:
The probability of drawing four white balls is 0.03014
Step-by-step explanation:
Given;
7 red balls
5 white balls
total number of balls = 7 + 5 = 12
each time a white ball is drawn, the probability = 5 / 12
The probability of drawing four white balls is given by;
P= P(1st white AND 2nd white AND 3rd white AND 4th white)
P = P(1 st white) x P(2nd white) x P(3rd white) x P(4th white)
P = (5 / 12) x (5 / 12) x (5 / 12) x (5 / 12) (with replacement)
Therefore, the probability of drawing four white balls is 0.03014
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<h2>Steps:</h2>
So for this, we will be doing a system of equations. Using the info from our question, our two equations are:
(let x = greater number and y = lesser number)
Now, for this I will be using the substitution method. Since we know that x = 4y - 1, substitute that into the second equation:
From here we can solve for y. Firstly, combine like terms:
Next, subtract 4y on both sides of the equation:
Next, multiply both sides by -1:
Now that we know the value of y, substitute it into either equation to solve for x:
In short, <u>5 is the lesser number and 19 is the greater number.</u>