Layla has a coin that has a 60%, percent chance of showing heads each time it is flipped. She is going to flip the coin 5 times.

Question

2 years ago

11

Let X represent the number of heads she gets. What is the probability that she gets more than 3 heads?

2 answers:

Semenov [28] · Answer 1 · 2022-11-26T05:00:28+03:00

Answer:

0.33696

Step-by-step explanation:

Given that:

Probability of showing up head (p) = 0.6

Number of flips = number of trials = 5

Probability of getting more than 3 heads

P(x = x) = nCx * p^x * (1 - p)^(n-x)

P(x> 3) = p(4) + p(5)

P(x = 4) = 5C4 * 0.6^4 * 0.4^1 = 0.2592

P(x = 5) = 5C5 * 0.6^5 * 0.4^0 = 0.07776

Hence,

0.2592 + 0.07776

= 0.33696

bekas [8.4K] · Answer 2 · 2022-11-26T06:03:05+03:00

3 0

Answer:

P(X=3)=0.3456~0.35

Step-by-step explanation:

khan acedemy told me when i got it wrong lol