Layla has a coin that has a 60%, percent chance of showing heads each time it is flipped. She is going to flip the coin 5 times.
Let X represent the number of heads she gets. What is the probability that she gets more than 3 heads?
2 answers:
Answer:
0.33696
Step-by-step explanation:
Given that:
Probability of showing up head (p) = 0.6
Number of flips = number of trials = 5
Probability of getting more than 3 heads
P(x = x) = nCx * p^x * (1 - p)^(n-x)
P(x> 3) = p(4) + p(5)
P(x = 4) = 5C4 * 0.6^4 * 0.4^1 = 0.2592
P(x = 5) = 5C5 * 0.6^5 * 0.4^0 = 0.07776
Hence,
0.2592 + 0.07776
= 0.33696
Answer:
P(X=3)=0.3456~0.35
Step-by-step explanation:
khan acedemy told me when i got it wrong lol
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