Answer:1.45
Step-by-step explanation:
Divide.
You could subtract the denominator fro the numerator which would give you a total sum of 1 thousand an fifty five
120 ways. More details in attachment.
Answer: The company must sold 382 units to break even.
Step-by-step explanation:
Hi, there is no question asked, so I suppose that you need to find the number of items (x) to break even.
To answer this question we have to equal both sides of the equations:
Since costs equal its income:
C=R
So:
38x +19100= 88x
Solving for x
19100= 88x-38x
19100=50x
19100/50 =x
382=x
The company must sold 382 units to break even.
Feel free to ask for more if needed or if you did not understand something.
Answer:

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

And the standard deviation for the sampling distribution would be:

So then the answer is TRUE
Step-by-step explanation:
Let X the random variable of interest and we know that the true mean and deviation for this case are given by:

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

And the standard deviation for the sampling distribution would be:

So then the answer is TRUE