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iogann1982 [59]
3 years ago
14

My quiz had 15 questions, I got a score of 67.8%. how many questions did I get wrong?

Mathematics
2 answers:
Ne4ueva [31]3 years ago
4 0
You take 67.8/100×15
10.17
then take 15-10.17 the answer will be the wrongs u got
=4.83
timama [110]3 years ago
3 0
67.8/100×15=10.17
15-10.17 <span>=4.83</span>
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Could someone help me on my assignment?
Degger [83]
First box (under 1) is 7, next box (above 12.5) is 6.5 and the last box is 16
8 0
2 years ago
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Using the following equation, find the center and radius:
rodikova [14]

Answer: 4) The center is located at (1, 3), and the radius is 6

Step-by-step explanation:

Solve the general equation of the circle.

x^2 -2x +1+ y^2-6y+9= 26+1+9 (x-1)^2+(y-3)^2=36=6^2

Hence, the coordinates of the center (1,3) And the radius will be 6

4 0
3 years ago
How is the process of finding the surface area of a rectangular prism the same as finding the surface area of a triangular prism
harina [27]

Answer:

see the explanation

Step-by-step explanation:

we know that

The surface area of a prism is given by the formula

SA=2B+PH

where

B is the area of the base

P is the perimeter of the base

H is the height of the prism

For both prism the formula is the same

How is it different?

Rectangular prism

The area of the base is given by the formula

A=LW -----> is the area of rectangle

where

L is the length and W is the width of rectangle

The perimeter of the base is given by

P=2(L+W) ---> is the perimeter of rectangle

The height H is the same in both cases

Triangular prism

The area of the base is given by the formula

A=\frac{1}{2} (b)(h) -----> is the area of the triangular base

where

b is the base of triangle and h is the height of triangle

The perimeter of the base is given by

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where

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The height H is the same in both cases

3 0
3 years ago
Read 2 more answers
Please help me with 25-29!!
vredina [299]
25-29 ok so first do 9-5 equals 4
4 0
3 years ago
What two numbers multiply to 10 and add to -29 ?
Degger [83]
Xy=10
x+y=29

subtract x from both sides for second equation

y=-x-29
subsitute in second equaiton
x(-x-29)=10
-x^2-29x=10
add x^2+29x to both sides
x^2+29x+10=0
quadratic formula
if you have
ax^2+bx+c=0,
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

so
x^2+29x+10=0
a=1
b=29
c=10
x=\frac{-29+/- \sqrt{(-29)^{2}-4(1)(10)} }{2(1)}
x= \frac{-29+/- \sqrt{841-40} }{2}
x= \frac{-29+/- \sqrt{801} }{2}
x= \frac{-29+/- 3\sqrt{89} }{2}

x= \frac{-29- 3\sqrt{89} }{2} or \frac{-29+ 3\sqrt{89} }{2}
those are the 2 numbers
aprox=-28.65 and -0.349


5 0
2 years ago
Read 2 more answers
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