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mafiozo [28]
3 years ago
7

Mr. Kim borrows $3,000 to pay for house repairs. The simple interest is 8% for one year.

Mathematics
2 answers:
Archy [21]3 years ago
5 0

Answer:

3240

Step-by-step explanation:

If the simple interest is 8%, Mr. Kim will have to pay $3000, and the simple interest, which will be 8% of $3000.

You can write it in two ways:

3000+3000*0.08= 3240

or

3000*1.08= 3240

vredina [299]3 years ago
3 0

Answer:

SI=PTR÷100

=3000×1×8÷100

=2400

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14 lessons costs $210. What would 72 lessons cost
Oksi-84 [34.3K]

Answer:

$1,080

Step-by-step explanation:

To solve, we can make a proportion

14 lessons are $210 and 72 lessons are $x

14/210=72/x

Cross multiply

14*x=210*72

14x=15120

To solve for x, we need to get x by itself. Since x is being multiplied by 14, divide both sides by 14.

14x/14=15120/14

x=1080

So, 72 lessons will cost $1,080

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3 years ago
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5 x a x 5 x a simplified
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What are the square roots of 121? Select two answers from the choices below.
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Step-by-step explanation:

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Write the expression that shows "3 times the sixth power of ten."
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How many sequences of 0s and 1s of length 19 are there that begin with a 0, end with a 0, contain no two consecutive 0s, and con
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65 sequences.

Lets solve the problem,

The last term is 0.

To form the first 18 terms, we must combine the following two sequences:

0-1 and 0-1-1

Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent

So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:

2x + 3y = 18

Case 1: x=9 and y=0

Number of ways to arrange 9 identical 2-term sequences = 1

Case 2: x=6 and y=2

Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28

Case 3: x=3 and y=4

Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35

Case 4: x=0 and y=6

Number of ways to arrange 6 identical 3-term sequences = 1

Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65

Hence the number of sequences are 65.

Learn more about Sequences on:

brainly.com/question/12246947

#SPJ4

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