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koban [17]
2 years ago
6

Write an expression for "777 divided by ccc."

Mathematics
2 answers:
vampirchik [111]2 years ago
8 0
500892 divided by cccc
Hope this helps
nirvana33 [79]2 years ago
8 0

Answer:

7/c

Step-by-step explanation:i said so and im right so put it in and try to prove me wronge :)

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9x-8(x-6)=52 what is the answer
Effectus [21]

Answer:

x = 4

Step-by-step explanation:

Step 1: Write equation

9x - 8(x - 6) = 52

Step 2: Solve for <em>x</em>

  1. Distribute -8: 9x - 8x + 48 = 52
  2. Combine like terms: x + 48 = 52
  3. Subtract 48 on both sides: x = 4

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

9(4) - 8(4 - 6) = 52

36 - 8(-2) = 52

36 + 16 = 52

52 = 52

7 0
3 years ago
Give that 5x=3(mod7)find x
pychu [463]

Answer Below!

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5 0
2 years ago
E. solve for y<br>-3y+6​
Rudik [331]

Answer:

y = 2

Step-by-step explanation:

-3y + 6 = 0

-3y = -6

y = -6/-3

y = 6/3

y = 2

6 0
3 years ago
Read 2 more answers
Plz hurry!!!! thank you!!!!
Nikitich [7]

Answer:

Area of trapezium = 4.4132 R²

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and ∠NMK = 65°

OT = R.

⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).

Now, sum of interior angles in a quadrilateral of 4 sides = 360°.

⇒ x + x + 65° + 65° = 360°

⇒ x = 115°.

Here, NS is a tangent to the circle and ∠NSO = 90°

consider triangle NOS;

line joining O and N bisects the angle ∠MNP

⇒ ∠ONS = \frac{115}{2} = 57.5°

Now, tan(57.5°) = \frac{OS}{SN}

⇒ 1.5697 = \frac{R}{SN}

⇒ SN = 0.637 R

⇒ NP = 2×SN = 2× 0.637 R = 1.274 R

Now, draw a line parallel to ST from N to line MK

let the intersection point be Q.

⇒ NQ = 2R

Consider triangle NQM,

tan(∠NMQ) = \frac{NQ}{QM}

⇒ tan65° = \frac{NQ}{QM}

⇒ QM = \frac{2R}{2.1445}

QM = 0.9326 R .

⇒ MT = MQ + QT

          = 0.9326 R + 0.637 R  (as QT = SN)

⇒ MT = 1.5696 R

⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R

Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).

⇒ A = (\frac{NP + MK}{2}) × (ST)

       = (\frac{1.274 R + 3.1392 R}{2}) × 2 R

       = 4.4132 R²

⇒ Area of trapezium = 4.4132 R²

5 0
3 years ago
Find the length AB round your answer to the tenth
Kobotan [32]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

AB =  \sqrt{ ({3 - ( - 2)})^{2} +  ({4 - 0})^{2}  }  \\

AB =  \sqrt{ ({3 + 2})^{2} +  {4}^{2}  }

AB =  \sqrt{ {5}^{2} +  {4}^{2}  }

AB = \sqrt{25 + 16}

AB = \sqrt{41}

AB = 6.403

AB = 6.4

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

3 0
2 years ago
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