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koban [17]
3 years ago
6

Write an expression for "777 divided by ccc."

Mathematics
2 answers:
vampirchik [111]3 years ago
8 0
500892 divided by cccc
Hope this helps
nirvana33 [79]3 years ago
8 0

Answer:

7/c

Step-by-step explanation:i said so and im right so put it in and try to prove me wronge :)

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H=10 cm <br>r= 7cm <br>calculate the volume of the cylinder ​
Stels [109]

Answer:

V = 1538.6 cm^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2h  where r is the radius and h is the height

V = pi (7)^2 10

V = 3.14 (49)10

V = 1538.6 cm^3

7 0
3 years ago
Read 2 more answers
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)
vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

x^{\frac{2}{3}}+y^{\frac{2}{3}}=4

We have to find the equation of tangent line to the given curve at point (-3\sqrt3,1)

By using implicit differentiation, differentiate w.r.t x

\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0

Using formula :\frac{dx^n}{dx}=nx^{n-1}

\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}

\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}

\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}

Substitute the value x=-3\sqrt3,y=1

Then, we get

\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}

\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}

Slope of tangent=m=\frac{1}{\sqrt3}

Equation of tangent line with slope m and passing through the point (x_1,y_1) is given by

y-y_1=m(x-x_1)

Substitute the values then we get

The equation of tangent line is given by

y-1=\frac{1}{\sqrt3}(x+3\sqrt3)

y-1=\frac{x}{\sqrt3}+3

y=\frac{x}{\sqrt3}+3+1

y=\frac{x}{\sqrt3}+4

This is required equation of tangent line to the given curve at given point.

8 0
4 years ago
Complete the point-slope equation of the line through (6, 4) and (7, 2)
ra1l [238]

Answer:

15

Step-by-step explanation:

8 0
4 years ago
find the area of a triangular shaped land having the length of three sides 20,34 M and 42 respectively in metre square Anna and
matrenka [14]

Step-by-step explanation:

if I understand you correctly, then the 3 sides are

a = 20 m

b = 34 m

c = 42 m

under this assumption the best is to use Heron's Formula to get the area :

s = (a + b + c)/2

area = sqrt(s(s - a)(s - b)(s - c))

in our case

s = (20 + 34 + 42)/2 = 96/2 = 48

area = sqrt(48(48-20)(48-34)(48-42)) =

= sqrt(48×28×14×6) = sqrt(112,896) =

= 336 m²

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2 years ago
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