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Alex787 [66]
2 years ago
10

Most television showsUse 13 minutes of every hour for commercials leaving the remaining 47 minutes for the actual show. One popu

lar told me that she wants to change the ratio of commercial time to Showtime to be 3:7. Which way would have left commercials if the if you were still watching for two hours?
Mathematics
1 answer:
babunello [35]2 years ago
6 0

Answer:

Step-by-step explanation:née

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|2x+1|=-13 <br> A) no solution
sweet [91]

2x + 1 = -13

2x = -13 -1

2x = -14

x = -14 / 2

x = -7

3 0
3 years ago
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Which number (s) below represents a repeating decimal? -2/5, -7, 3/7, 11/12
Ray Of Light [21]

Step-by-step explanation: Arrange the terms in ascending order: -7, -2/5, 3/9, 11/12.

Hope this helps! :D

-TanqR

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3 years ago
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PLSSS HELP IF YOU TURLY KNOW THISS
Montano1993 [528]
It is 7

2*2x = 4x + 2 = 30

4x = 28

x = 7
6 0
3 years ago
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Need this really quick plz
Oduvanchick [21]

Answer:

Let

x=sin-¹u

Sinx=u

let y=tan-¹v

tany=v

Substituting

Sin[x + y]

Applying the sine expansion

Sinxcosy + CosxSiny

Recall x =Sin-¹u

y=tan-¹v

Sin(Sin-¹u)Cos(tan-¹v) +Cos(sin-¹u)Sin(tan-¹v)

Now at this point

Here's what you do

For the first expression

Sin(Sin-¹u)

Let's simplify this

Let P = Sin-¹u

Taking sine of both sides

SinP=u

Draw a Right angled angle for this

Since Sine from SOHCAHTOA is OPP/HYP

Where P is the angle and u is the opposite and 1 is the hypotenuse since u is the same as u/1

substituting Sin-¹u = P

You have

Sin(Sin-¹u) = SinP

and from the triangle you drew

SinP = u

Taking the second express

Cos(tan-¹v)

Let Q=Tan-¹v

taking tan of both sides

tanQ=v

Draw a right angled triangle for this too

Since Tan from SOHCAHTOA is OPP/ADJ

Find the Hypotenuse cos you'll need it

Now Let's do the substitution again

We first said tan-¹v = Q

When we substitute it in Cos(tan-¹v)

We have CosQ

Cos Q from the second right angle triangle you drew is 1/√1+v²

Because CAH is adj/Hyp

So

the first part of the original Express

Which is

Sin(Sin-¹u)Cos(tan-¹v) is now simplified to

u(1/√1+v²).

Let's Move to the second part of the Original Expression

Cos(Sin-¹u)Sin(tan-¹v)

From our first solution

We said Sin-¹u= P

So replacing it here

we have Cos(sin-¹u) = CosP

let's leave the second one for now which is sin(tan-1v) We'll deal with this after the first

so Cos(Sin-¹u) = CosP

we can still use our first Right angle triangle for this because the angle was P.

so Cos P from that triangle will be

CosP= √1-u²

Now onto the next

Sin(tan-¹v)

From the Second solution of the first we did

we said let Tan-¹v =Q

Substituting this

we have

Sin(tan-¹v) = SinQ

using the second Right angle triangle because its angle is Q

We have

SinQ= v/√1+v²

Answer for second phase Which is

Cos(sin-¹u)Sin(tan-¹v) = √1-u²(v/√1+v²)

We're done

compiling our answers

The answer to

Sin(Sin-¹u - tan-¹v) = u(1/√1+v²) + [(√1-u²)(v/√1+v²)]

You can still choose to factor out 1/√1+v² since it appears on both sides

8 0
2 years ago
Not including tax, 14 pieces of clothing cost $107. Pants cost $12.50 and shirts cost $4.00. No other types of clothes were purc
galben [10]
I would say that could one equation 12.5p+4s=107
4 0
3 years ago
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