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notka56 [123]
3 years ago
12

A housepainter mixed 5 gal of blue paint with every 9 gal yellow paint in order to make a green paint. Which ratio of gallons of

blue paint to gallons of yellow paint will make the same shade of green
Mathematics
1 answer:
zepelin [54]3 years ago
7 0

Answer: the ratio of gallons of blue paint to gallons of yellow paint that will make the same shade of green is 5/9

Step-by-step explanation:

The housepainter mixed 5 gallons of blue paint with every 9 gallons of yellow paint in order to make a green paint.

To determine the ratio of gallons of blue paint to gallons of yellow paint that will make the same shade of green, we will divide the gallons on blue paint required by the gallons of yellow paint required. It becomes

The ratio is 5/9 = 5:9

It means that for every 5 gallons of blue paint, 9 gallons of of yellow paint is required

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Are 25 milligrams lighter or heavier than 25 centigrams
masya89 [10]

Answer:

<em>25 mg. is lighter than 25 cg.</em>

<em />

Step-by-step explanation:

<em>Well,</em>

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<em>The prefix "milli" means thousandth and the prefix "centi" means hundredth.  So a milligram will be one-tenth of a centigram.</em>

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8 0
2 years ago
Read 2 more answers
Please prove this........​
Crazy boy [7]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    →     C = π - (A + B)

                                    → sin C = sin(π - (A + B))       cos C = sin(π - (A + B))

                                    → sin C = sin (A + B)              cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS:                        (sin 2A + sin 2B) + sin 2C

\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C

\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C

\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C

\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)

\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]

\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B

\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C    \checkmark

7 0
3 years ago
each time kim pour water from a jug into a glass, exactly 10% of the water remaining in the jug is used. What is the minimum num
Gnoma [55]

The <em><u>correct answer</u></em> is:

At least 7 times.

Explanation:

Since 10% of the water in the jug is removed each time, this means that 100-10=90% of the water remains.

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0.5 < 0.9^x

To solve this, we will use logarithms:

\log_{0.9}(0.5)

4 0
3 years ago
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