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Alexxandr [17]
4 years ago
5

ANSWER PLZ QUICK AND FAST

Mathematics
2 answers:
Sphinxa [80]4 years ago
4 0

36.1%

All you have to do is move the decimal to the left 2 times because 100 has 2 0's and a percentage is a piece of 100

.361*100=36.1%

Hope this helps!! Good Luck.

eduard4 years ago
3 0

Multiply the decimal fraction by 100 ( this is same as moving the decimal point 2 places to the right,

So 0.361 = 36.1 % (answer)

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Formula to find the missing number Faces:15 vertices:15 edges:?
gtnhenbr [62]

Answer:

Step-by-step explanation:

Euler's formula is

V - E + F = 2

Givens

V = 15

E = 15

F = ?

Solution

15 - 15 + F = 2

F = 2

I'm not sure this makes sense, but it is what the formula gives you.

7 0
3 years ago
An investment of $100 is now valued at $149.18 the interest rate is 8% compounded continuously about how long has the money been
deff fn [24]

question: An investment of $100 is now valued at $149.18 the interest rate is 8% per year, compounded continuously about how long has the money been invested

Answer:

5.2 years

Step-by-step explanation:

Applying

A = P(1+R/100)ⁿ.......................... Equation 1

Where A = amount, P = principle, R = rate, n = time.

From the question,

Given: A = $149.18, P = $100, R = 8%

Substitute these values into equation 1 and solve for n

149.18 = 100(1+8/100)ⁿ

149.18/100 = (1+8/100)ⁿ

1.4918 = (1+0.08)ⁿ

1.4918 = (1.08)ⁿ

Taking the Logarithm of both side

Log(1.4918) = Log(1.08)ⁿ

Log(1.4918) = nLog(1.08)

n = Log(1.4918)/Log(1.08)

n = 0.1737/0.0334

n = 5.2 years.

7 0
3 years ago
An airplane leaves an airport and flies due west 150 miles and then 170 miles in the direction S 49.17°W. How far is the plane f
Sphinxa [80]

Answer:

Distance between plane and airport is 134.4 miles.

Step-by-step explanation:

Given : An airplane leaves an airport and flies due west 150 miles and then 170 miles in the direction S 49.17°W.

To find : How far is the plane from the airport.

Solution : Distance from airport to west is 150 miles and then 170 miles in the direction south  and angle form is S 49.17° W

Refer the attached picture for clearance.

Applying law of cosines

c^2=a^2+b^2-2ab Cos(C)

c=\sqrt{a^2+b^2-2ab Cos(C)}

where a= 150 miles

b=170 miles

C=   49.17° angle in degree

c = distance between plane from the airport

Put values in the formula,

c=\sqrt{a^2+b^2-2ab Cos(C)}

c=\sqrt{150^2+170^2-2(150)(170) Cos(49.17^{\circ})}

c=\sqrt{22500+28900-51000(0.653)}

c=\sqrt{51400-33303}

c=\sqrt{18057}

c=134.37

Therefore, Distance between plane and airport is 134.4 miles.

5 0
3 years ago
Read 2 more answers
Hey plz help and show work
blsea [12.9K]
The dog house consists of two geometric objects, triangular prism and rectangular prism.

First, find the surface area of triangular prism
The triangular prism consists of
base of triangle (b) = 3 ft
height of triangle (h) = 2.5 ft
height of prism or length of rectangle (l) = 4 ft
side of triangle or width of rectangle (w) = 2.5 ft

Now, calculate the area
area of tp = area of two triangle + area of 2 rectangle
area of tp = (2 × 1/2 × b × h) + (2 × l × w)
area of tp = (2 × 1/2 × 3 × 2) + (2 × 4 × 2.5)
area of tp = 6 + 20
area of tp = 26 ft²

Second, find the surface area of rectangular prism
The rectangular prisms consists of
length (l) = 3 ft
width (w) = 4 ft
height (h) = 2 ft

Now, calculate the area
area of rp = area of back and front rectangle + area of left and right rectangle
area of rp = (2 × l × h) + (2 × w × h)
area of rp = (2 × 3 × 2) + (2 × 4 × 2)
area of rp = 12 + 16
area of rp = 28 ft²

Third, add both of the area
area = area of tp + area of rp
area = 26 + 28
area = 54 ft²

The area of the dog house is 54 ft
²
6 0
3 years ago
The difference between five and twice a number, x, is one.
tia_tia [17]
" the difference " means subtract

the difference between 5 and twice a number x is 1

5 - 2x = 1 <== ur equation
-2x = 1 - 5
-2x = - 4
x = -4/-2
x = 2 <== ur solution
5 0
4 years ago
Read 2 more answers
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