Answer:
1000 times
Step-by-step explanation:
Given:
The Sun is roughly 10^2 times as wide as the Earth.
The Star KW Sagittarii is roughly 10^5 times as wide as the Earth.
Question asked:
About how many times as wide as the Sun is KW Sagittarii?
Solution:
Let the width of the earth = 
As the Sun is roughly 10^2 times as wide as the Earth, hence the width of the sun = 
And as the Star KW Sagittarii is roughly 10^5 times as wide as the Earth, hence the width of the Star = 
Now, to find that how many times width of the Star KW Sagittarii is as respect to the width of the Sun, we will simply divide:
Width of the Star KW Sagittarii = 
Width of the Sun = 

x canceled by x

Therefore, Star KW Sagittarii is 1000 times wider than Sun.
<em>First of all we calculated width of Sun in terms of width of earth and then calculated the width of the Star in terms of earth and for comparison we did simple division that showed that the Star KW Sagittarii is 1000 times wider than the Sun.</em>
<em />
By the intersecting chords theorem, you have

20 percent
If you cross multiply 30 w/ 100 and then divide it by 150 you will get 20.
Answer:
A. factors.
Step-by-step explanation:
The correct option is - A. factors.
Reason -
The variables "stepping rate" and "step height" are the factors because a activity is performed in which stepping at one of the three stepping rates at one of the two possible heights for three minutes.
The activity is based on both the variables stepping rate and step height.
You have 6 variables with 2 levels each. Thus 2*2*2*2*2*2 or 2^6 or 64.