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3 years ago

Someone plz help me Idk what to do idk which answer It is I’ll give brainlist and points

Mathematics

2 answers:

GalinKa [24]3 years ago

7 0

Answer:

b (-3/5)

Step-by-step explanation:

First, distribute the -2 on the left side

-2x-2=3x+1

now, add 2 to both sides

-2x=3x+3

subtract 3x from both sides

-5x=3

divide both sides by -5

x=-3/5

HTH :)

matrenka [14]3 years ago

3 0

Answer:

It's b)

Step-by-step explanation:

-2 (x + 1) = 3x + 1

-2x -2 = 3x + 1

-3x +2

-5x = 3

-5x/-5 = x

3/-5 = -0.6

x = - 0.6 (-3/5 as a fraction)

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HELPPPPPPPPP PLEASE!!! :(

erastovalidia [21]

Answer:

x = 25

Step-by-step explanation:

Given:

∠A = ∠B (Vertically opposite angles)
∠A = (7x - 8)°
∠B = (6x + 17)°

Since ∠A is equivalent to ∠B...

$\implies (7x - 8)= (6x + 17)$

Open the parenthesis:

$\implies 7x - 8= 6x + 17$

Add 8 both sides:

$\implies 7x - 8 + 8= 6x + 17 + 8$

Simplify both sides:

$\implies 7x = 6x + 25$

Subtract 6x both sides:

$\implies 7x - 6x = 6x - 6x + 25$

Simplify both sides:

$\implies x = 25$

7 0

2 years ago

Read 2 more answers

What’s the circumference and the area for 4 in

Paladinen [302]

Answer:

C = 25.12 , A = 50.24

Step-by-step explanation:

$C = \pi d\\A = \pi r^{2}$

C = 8 * 3.14 = 25.12

A = (4*4) * 3.14 = 50.24

5 0

3 years ago

Ann increased the quantities of all the ingredients in a recipe by 60\%60%60, percent. She used 808080 grams (\text{g})(g)left p

kari74 [83]

Answer:

50 grams

Step-by-step explanation:

Let the amount of cheese required by the recipe be "x"

Ann increased 60% from original amount and then used up 80 grams. Thus:

Original, increased by 60%, became 80

This translated to algebraic equation would be:

x + 0.6x = 80

Note: 60% = 60/100 = 0.6

So we can solve the above equation for "x" and get our answer. Shown below:

$x + 0.6x = 80\\1.6x=80\\x=\frac{80}{1.6}\\x=50$

Hence,

the recipe required 50 grams of cheese

6 0

3 years ago

In a triangle a=20 and c=29 but how long is side b ?

Afina-wow [57]

A^2+b^2=c^2
20^2+b^2=29^2
400+b^2=841
-400. -400
b^2=√441
b=21

6 0

3 years ago

The gross weight of a truck containing 30 pigs is 8 tons 1,123 pounds and 6 ounces. The average weight of one pig is 95 pounds 1

irakobra [83]

Answer: The net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

The weight of the empty truck is 7 tons 254 pounds 10 ounces.

Step-by-step explanation:

Since we have given that

The gross weight of a truck containing 30 pigs = 8 tons 1123 pounds 6 ounces

Average weight of one pig = 95 pounds 10 ounces

Now,

We know that

$1\text{ pound}=16\text{ ounces}$

So,

$\text{Gross weight of truck containing 30 pigs}\\=8\text{ tones }1123\times 16+6\text{ ounces}\\=8\text{ tons }17974\text{ ounces}$

Similarly,

$\text{ average weight of one pig }\\=95\times 16+10\text{ ounces}\\=1530\text{ ounces}$

So, Net weight of the pigs in the truck

$1530\times 30\\ =45900\text{ ounces}\\\\=\frac{45900}{16}\\\\=2868\text{ pounds }12\text{ ounces}\\\\=1\text{ ton }868\text{ pounds }12\text{ ounces }$

So, the net weight of the pigs of the truck is 1 ton 868 pounds 12 ounces.

Now, we'll find the weight of the empty truck is given by

$\text{Gross weight of a truck containing} -\text{ Net weight of pigs in the truck}\\=8\text{ tons}1123\text{ pounds}6\text{ ounces}-1\text{ton }868\text{ pounds }12\text{ounces}\\=(8\times 2000\times 16+1123\times 16+6)-(1\times 2000\times 16+868\times 16-12)\\=273974\text{ ounces}-45900\text{ ounces}\\=228074\text{ounces }\\=7\text{ tons }254\text{ pounds }10\text{ ounces}$

Hence, the weight of the empty truck is 7 tons 254 pounds 10 ounces .

4 0

3 years ago