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pishuonlain [190]
2 years ago
11

What is the value of the expression below when b = 4 and c=5?

Mathematics
1 answer:
Ratling [72]2 years ago
3 0

Answer:

C. 107

Hope this helps! :)

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(–5) + [(–3) + (–2)] = [(–5) + (–2)] + (–3) answer it fast as you can ​
Naily [24]
Ok done. Thank to me :>

7 0
2 years ago
Brian needs to start planning for an upcoming move. He is choosing two different size boxes to pack the majority of his stuff. T
GenaCL600 [577]

Solution:

Given,

Volume of the-

First cube box=1728 in³

Second cube box=13824in³

We know that volume of cube =a³

So for the first box

a³= 1728 in³

a= 12 in

Now, surface area of the first box

6a²= 6×(12)²

= 864 in²

and for the second box

b³= 13824 in³

b= 24 in

Now, the surface area of the second box

6b²= 6×(24)²

= 3456 in²

Now, the ratio of the surface area of first box to the second box will be

864:3456

=1:4

The surface area of the larger of two boxes is

3456 in²

5 0
2 years ago
✎Question:Amirah is 4 years elder than Priya and Shirley is 2 years younger than Priya. If the sum of their ages is 47, find the
Gnom [1K]

Answer:

Priya's age = 15

Amirah's age = 19

Shirley's age = 13

Step-by-step explanation:

Let x be the age of Priya.

According to the question,

Amirah's age = x + 4

Shirley's age = x - 2

Their sum is 47.

So,

x + 4 + x + x - 2 = 47

3x + 2 = 47

3x = 47 - 2

3x = 45

x = 45/3

x = 15

So,

Priya's age = 15

Amirah's age = 15 + 4 = 19

Shirley's age = 15 - 2 = 13

7 0
3 years ago
Read 2 more answers
Listed below are prices in dollars for one night at different hotels in a certain region. Find the​ range, variance, and standar
Artyom0805 [142]

Answer:

Range = 115$

Standard Deviation = 43.76$

Variance = 1915.142$

Option  A) The measures of variation are not very useful because when searching for a​ room, low​ prices, location, and good accommodations are more important than the amount of variation in the area.

Step-by-step explanation:

We are given the data for  prices in dollars for one night at different hotels in a certain region.

234, 160, 119, 131, 218, 207, 146, 141        

Range:

Sorted data: 119, 131, 141, 146, 160, 207, 218, 234

\text{Range} = 234-119 = 115\$

Standard Deviation:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{1356}{8} = 169.5

Sum of squares of differences = 4160.25 + 90.25 + 2550.25 + 1482.25 +  2352.25 + 1406.25 + 552.25 + 812.25 = 13406

\sigma = \sqrt{\dfrac{13406}{7}} = 43.76\$

Variance =

\sigma^2 = 1915.142\$

Measure of variance for someone searching for room:

Option  A) The measures of variation are not very useful because when searching for a​ room, low​ prices, location, and good accommodations are more important than the amount of variation in the area.

5 0
3 years ago
PLEASE HURRY!!!!!<br> EXPLAIN why or why not.
Sladkaya [172]

Answer:

The graph is not a line of best fit as there are not an equal number of data points on each side of the line

Step-by-step explanation:

Brainliest would be appreciated

3 0
2 years ago
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