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3 years ago

I bought a car of 650,000 andsold it for 520,000. Find thelost Percent ?

Mathematics

1 answer:

Tom [10]3 years ago

7 0

Answer:

20% decrease in value.

Step-by-step explanation:

Do 650,000 divided by 100 to find what 1% of the original price is:

650,000 divided by 100 = 6,500

To find what percentage of the original price 520,000 is, we divide it by 1% of the original cost (6,500):

520,000 divided by 6,500 = 80 (percent)

So if 520,000 is 80% of 650,000 the car has decreased in value by 20%.

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x=14

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8 4/5 - 2/3 - ? = 3 1/10

Dimas [21]

Answer: 5 1/30

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8 + 4/5 - 2/3 - 3 - 1/10 = 5 + 1/30

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2 years ago

A town population of children increased from 367 to 421 during the past year which equation showes how to find the percentage in

klemol [59]

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5.7%

Step-by-step explanation:

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2 years ago

A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a

zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

$\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}$

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

$\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}$

Hence the answer is 0.1157

(ii) None is defective becomes

$\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}$

hence the answer is 0.4823

(iii) All are defective

$\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}$

(iv) At least one is defective

This is 1 - probability that none is defective

$\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}$

Hence the answer is 0.5177

3 0

1 year ago

What is the ratio of 65*3^17 to 65*3^14

solniwko [45]

<span>The ratio of 65*3^17 to 65*3^14 can be found as follows:

(65) (3^17) 65
--------------- = ----- * 3^(17-14) = 1 * 3^3 = 27 (answer)
(65) (3^14) 65</span>

3 0

3 years ago

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I bought a car of 650,000 andsold it for 520,000. Find thelost Percent ?​

I bought a car of 650,000 andsold it for 520,000. Find thelost Percent ?