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3 years ago

8

Find the slope-intercept form of the line that passes through given the point and has the given slope. Include your work in your

final answer. Type your answer in the box provided or use the upload option to submit your solution.
(-1, 0)
m = -2

1 answer:

lyudmila [28]3 years ago

6 0

Answer:

$y=-2x-2$

Step-by-step explanation:

The equation of the line with the slope $m$ passing trough the point $(x_1,y_1)$ is

$y-y_1=m(x-x_1)$

In your case, the slope of the line is $m=-2$ and line is passing through the point $(-1,0),$ then

$m=-2,\\ \\x_1=-1\\ \\y_1=0$

Substitute these values into the equation above:

$y-0=-2(x-(-1))\\ \\y=-2(x+1)\\ \\y=-2x-2$

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If the distance from A (5,6) to B (1, b) is twice the distance from B to

Nimfa-mama [501]

Answer:

The possible values of $b$ are -2.944 and -9.055, respectively.

Step-by-step explanation:

From statement we know that $AB = 2\cdot BC$ . By Analytical Geometry, we use the equation of a line segment, which is an application of the Pythagorean Theorem:

$AB = 2\cdot BC$

$\sqrt{(x_{B}-x_{A})^{2}+(y_{B}-y_{A})^{2}} = 2\cdot \sqrt{(x_{C}-x_{B})^{2}+(y_{C}-y_{B})^{2}}$ (1)

Where:

$x_{A}$ , $x_{B}$ , $x_{C}$ - x-Coordinates of points A, B and C.

$y_{A}, y_{B}, y_{C}$ - y-Coordinates of points A, B and C.

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Then, we expand and simplify the expression above:

$x_{B}^{2}-2\cdot x_{A}\cdot x_{B} +x_{A}^{2} +y_{B}^{2}-2\cdot y_{A}\cdot y_{B} + y_{A}^{2} = 4\cdot (x_{C}^{2}-2\cdot x_{C}\cdot x_{B}+x_{B}^{2})+4\cdot (y_{C}^{2}-2\cdot y_{C}\cdot y_{B}+y_{B}^{2})$

$x_{B}^{2}-2\cdot x_{A}\cdot x_{B} + x_{A}^{2} +y_{B}^{2}-2\cdot y_{A}\cdot y_{B} + y_{A}^{2} = 4\cdot x_{A}^{2}-8\cdot x_{C}\cdot x_{B}+4\cdot x_{B}^{2}+4\cdot y_{C}^{2}-8\cdot y_{C}\cdot y_{B}+4\cdot y_{B}^{2}$

If we know that $x_{A} = 5$ , $y_{A} = 6$ , $x_{B} = 1$ , $y_{B} = b$ , $x_{C} = 1$ and $y_{C} = -3$ , then we have the following expression:

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$b^{2}-12\cdot b +52 = 4\cdot b^{2}+24\cdot b +132$

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This is a second order polynomial, which means the existence of two possible real solutions. By Quadratic Formula, we have the following y-coordinates for point B:

$b_{1} \approx -2.944$ , $b_{2} \approx -9.055$

In consequence, the possible values of $b$ are -2.944 and -9.055, respectively.

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