<em><u>The least amount of money you would need to invest per month is; $335</u></em>
<em><u>The anticipated rate of return on your investments is; 7%</u></em>
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- Amount to have been saved at the end of 10 years ≥ $40,000
Number of years of savings = 10 years.
- We want to find out the least amount to be invested per month.
There are 12 months in a year. Number of months in 10 years = 10 × 12 = 120 months.
- Thus, amount to be saved monthly = 40000/12 = $333.33
- Since the minimum amount he wants to save after 10 years is $40000, then we need to approximate the monthly savings in order.
Thus;
Monthly savings ≈ $335
- Now, for the anticipated rate of return on the investment, we know from S & P's that the benchmark on good rate of return for investment is a minimum of 7%.
- From online calculator, the worth of the investment after 10 years based on 7% rate of return yearly would be $57626.
Read more at; brainly.com/question/9187598
We know that $375 is spent for three weeks period
One week period is 5 days, so for three weeks periods, there are 15 days in total when the truck use the gasoline.
The amount spent on gasoline for one day is $375÷15 = $25
Answer:
80%
Step-by-step explanation:
Find 44/55 and multiply the result by 100%: (0.8)(100%) = 80% (completed)
Answer: C. (5, -10)
Step-by-step explanation:
When we have a point (x, y) and we do a dilation around (0,0) with a scale factor of A.
The new point will be:
(A*x, A*y)
in this case, the point is (3, -6) and the scale factor is (5/3)
Then the new point will be:
(3*(5/3), -6*(5/3)) = (5, -10)
1.
X = 0
2x + 1 = 0
X = 0
X = - ½ (Because we brought the numbers from one side to the other)
2.
Not sure for number 2.
